一个关于文件上传的页面.遇到错误.求大神指导指导-PHP 튜토리얼-php.cn

一个关于文件上传的页面.遇到错误.求大神指导指导

WBOY

풀어 주다： 2016-06-23 14:05:37

원래의

996명이 탐색했습니다.

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=gb2312" /><title>upload.</title><style type="text/css"><!--.STYLE2 {	font-family: "宋体";	font-weight: bold;}--></style></head><body><style type="text/css"><!--tr,td{font-size:10px}--></style><center>	<h1 class="STYLE2">upload your file</h1>	<p>	<table border="1" cellspacing="0" cellpadding="1" bordercolordark="#ffffff" bordercolorlight="#0000ff" width="400">	<form action="up_back.php" method="post" enctype="multipart/form-data">	<tr bgcolor="#ccccff">	<td>chose your file:</td>	<td><input type="file" name="upfile" size=32 /></td>	</tr>	<tr>	<td>describe:</td>	<td><input type="text" name="describe" size="42" /></td>	</tr>	<tr>	<td>owner:</td>	<td><input type="text" name="owner" size="42" /></td>	</tr>	<tr>	<td>submit:</td>	<td><center><input type="submit" value="submit" /></center></td>	</tr>	</form>	</table>	</p></center>		</body></html>

로그인 후 복사

这个是用来前台的页面调用下面的php.

<?phpif (!$_POST["upfile"]&&$_FILES["upfile"]["name"]==""){	echo "no file<p>";	echo "click<a href=\"up_forward.html\">there</a>return!";}else {	$filepath="upload/";	$name=$filepath.$_FILES["upload"]["name"];	while (file_exists($name))	{		$temp=explode(".", $name);		$name=$temp[0]."0".".".$temp[1];	}	if(move_uploaded_file($_FILES["upfile"]["tmp_name"], $name))	{		if ($_POST["owner"])		{			$owner=$_POST["owner"];		}		else 		{			$owner="NULL";		}		if ($_POST["describe"])		{			$describe=$_POST["describe"];		}		else		{			$describe="NONE";		}		$time=date("y-m-d H:m:s");		$content=$_FILES["upload"]["name"]."||".$owner."||".$describe."||".$time."\n";		file_put_contents("record.dat", $content.FILE_APPEND);		echo "name:".$_FILES["upfile"]["name"];		echo "<p>";		echo "is upload successfull.<p>";		echo "click<a href=\"up_forward.html\">there</a>return!";	}	else 	{		echo "upload error!<p>";		echo "fail!<p>";		echo "click<a href=\"index.php\">there</a>check!";	}}?>

로그인 후 복사

问题就在于上传之后,提示文件上传成功,但是upload文件夹里面文件名是0的倍数,而且没有文件格式..这个是怎么回事呢?

提示的错误就是下面这些..
Notice: Undefined index: upfile in D:\phpnow\htdocs\b\up_back.php on line 2

Notice: Undefined index: upload in D:\phpnow\htdocs\b\up_back.php on line 10

Notice: Undefined offset: 1 in D:\phpnow\htdocs\b\up_back.php on line 14

Notice: Undefined index: upload in D:\phpnow\htdocs\b\up_back.php on line 35
name:10.jpg

回复讨论(解决方案)

这一行 $name=$filepath.$_FILES["upload"]["name"];
第一个文件上传的name="file" , 没有"upload" 啊.

move_uploaded_file($_FILES["upfile"]["tmp_name"], $name) 后面参数没有带路径

move_uploaded_file($_FILES["upfile"]["tmp_name"], $name) 后面参数没有带路径

他的$name=$filepath.$_FILES["upfile"]["name"];就是这个

1.
if (!$_POST["upfile"]&&$_FILES["upfile"]["name"]=="")
==>
if ($_FILES["upfile"]["name"]=="")   //这样就能判断是否选择文件了

2.
$name=$filepath.$_FILES["upload"]["name"];
==》
$name=$filepath.$_FILES["upfile"]["name"];

3. 如果你的文件存在了。while循环不就成了死循环了吗，可以改为：
if(file_exists($name))
    {
        $temp=explode(".", $name);
        $name=$temp[0]."0".".".$temp[1];
    }
4.      $content=$_FILES[" upfile"]["name"]."||".$owner."||".$describe."||".$time."\n";

这一行 $name=$filepath.$_FILES["upload"]["name"];
第一个文件上传的name="file" , 没有"upload" 啊.
恩,确实这里有点毛病.谢谢你