各位大牛,消息想问个关于AJAX与PHP的问题,现在碰到这样的一个情况
我希望前端页面在点击某标签的时候,在下方可以显示我关于上方点击的标签进行关联的资料,代码如下
index.php
<html><head><script src="clienthint.js"></script> </head><body><form> First Name:<?php echo "<a>"; echo "<i class=\"dapei_partleft\"></i>"; echo "<span class=\"dapei_partmiddle\" title='teswt' name='test' onclick=\"showHint(1)\">test</span>"; echo "<i class=\"dapei_partright\"></i>"; echo " </a>"; echo "<a>"; echo "<i class=\"dapei_partleft\"></i>"; echo "<span class=\"dapei_partmiddle\" title='teswt1' name='test1' onclick=\"showHint(2)\">test</span>"; echo "<i class=\"dapei_partright\"></i>"; echo " </a>";?></form><p>Suggestions: <span id="txtHint"></span></p></body></html>
var xmlHttpfunction showHint(str){if (str.length==0) { document.getElementById("txtHint").innerHTML="" return }xmlHttp=GetXmlHttpObject()if (xmlHttp==null) { alert ("Browser does not support HTTP Request") return } var url="gethint.php"url=url+"?q="+strurl=url+"&sid="+Math.random()xmlHttp.onreadystatechange=stateChanged xmlHttp.open("GET",url,true)xmlHttp.send(null)} function stateChanged() { if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete") { document.getElementById("txtHint").innerHTML=xmlHttp.responseText } }function GetXmlHttpObject(){var xmlHttp=null;try { // Firefox, Opera 8.0+, Safari xmlHttp=new XMLHttpRequest(); }catch (e) { // Internet Explorer try { xmlHttp=new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { xmlHttp=new ActiveXObject("Microsoft.XMLHTTP"); } }return xmlHttp;}
<?php $q=$_GET["q"];//$select ="select * from test where cid='$q'";$hint="for($i=0;$i<2;$i++){......}";//Set output to "no suggestion" if no hint were found//or to the correct valuesif ($hint == ""){$response="no suggestion";}else{$response=$hint;}//output the responseecho $response;?>
通过 eval 和 create_function 都可实现
通过 eval 和 create_function 都可实现 谢谢。能举个例吗?因为我刚用了eval试了下。不行呢,操作如下
$hint='for($i=0;$i<2;$i++){.....}';
eval("\$hint = \"$hint\";");
$hint='for($i=0;$i<2;$i++){}';eval($hint);echo $i; //2
$hint = 'for($i=0;$i<2;$i++){}';if(2 == eval($hint.' return $i;')) echo 'ok';
$hint = 'for($i=0;$i<2;$i++){}';if(2 == eval($hint.' return $i;')) echo 'ok';
如果程序写作
for($i=0;$i<2;$i++){
如果程序写作
for($i=0;$i<2;$i++){
$hint = 'for($i=0;$i<2;$i++){}';if(2 == eval($hint.' return $i;')) echo 'ok';
$hint = 'for($i=0;$i<2;$i++){}';if(2 == eval($hint.' return $i;')) echo 'ok';
可能是:
标记不配套
id 重名
预先绑定的事件无效