JavaScript에서 두 문자열 일치

직장에서 두 개의 문자열이 일치하는 문제가 발생했습니다. 요구 사항은 다음과 같습니다. 각 문자열에는 최대 하나의 *가 포함되며, ?는 모든 길이의 문자열을 나타내는 무한한 수의

*를 가질 수 있습니다.

문자를 나타내며 두 ​​가지 충돌이 필요합니다

Javascript를 사용하여 다음과 같이 코드를 구현합니다.

[javascript] 
function checkMarchX() 
    { 
        var str1 = document.getElementById('str1').value; 
        var str2 = document.getElementById('str2').value; 
        var str1XPosition = str1.indexOf('*'); 
        var str2XPosition = str2.indexOf('*'); 
        if(str1XPosition!=-1 && str2XPosition!=-1)//两者twitter含有* 
        { 
           var position = str1XPosition>str2XPosition;//success 
            if( position!=0) 
            { 
                var patbeforeStr1 = str1.substring(0,position); 
                var patbeforeStr2 = str2.substring(0,position); 
               if(checkMarchQ(patbeforeStr1,patbeforeStr2)) 
               { 
                   //alert(str1+'与'+str2+"前半부분분冲突"); 
                   //然后对应后半부분분담进行测试 
                  var str1XBackPosition = str1.length-str1XPosition-1; 
                   var str2XBackPosition = str2.length-str2XPosition-1; 
                   var backposition = str1XBackPosition>str2XBackPosition?str2XBackPosition:str1XBackPosition; 
                   if (backposition==0) 
                   { 
                      Alert(str1+'与'+str2+"冲突"); 
                   } 
                  else 
                 { 
                      var patbackStr1 = str1.sub 문자열(str1.length-backposition,str1.length); 
                       var patbackStr2 = str2.substring(str2.length-backposition,str2.length); 
                      if(checkMarchQ(patbackStr1,patbackStr2)) 
                    { 
                         경고(str1+''+ str2+"입력"); 
                      } 
                  } 
              } 
           } 
            else 
            { 
                //alert(str1+'与'+str2+"앞부분분할"); 
                var str1XBackPosition = str1.length-str1XPosition-1; 
                var str2XBackPosition = str2.length-str2XPosition-1; 
                var backposition = str1XBackPosition>str2XBackPosition?str2XBackPosition:str1XBackPosition; 
               if (backposition==0) 
               { 
                  Alert(str1+'与'+str2+"冲突");  else { var patbackstr1 = str1.substring (str1.length-backposition, str1.length); 
                   var patbackStr2 = str2.substring(str2.length-backposition,str2.length); 
                  if(checkMarchQ(patbackStr1,patbackStr2)) 
                 { 
                     경고(str1+'与'+str2+"冲突") ; 
                  } 
               } 
           } 
        } 
        else if((str1XPosition==-1 && str2XPosition !=-1)||(str1XPosition!=-1 && str2XPosition==-1) )//유신한 글자가 있습니다* 
        { 
            var strX = str1XPosition==-1?str2:str1;//含有*字符串 
            var strNoX = str 1XPosition==-1? str1:str2;//不含*字符串 
            if (strX.length-1            { 
               var position = strX.indexOf('*'); 
               if(position==0) 
                { 
                  //alert(str1+'与'+str2+"前半부분분冲突"); 
                   var backposition = strX.length-position-1; 
                   if (backposition==0) 
                   { 
                      Alert(str1+'与'+str2+"冲突"); 
                   } 
                   else 
                  { 
                        var patbackStr1 = str1.substring(str1.length-backposition,str1.length); 
                       var patbackStr2 = str2.substring(str2.length-backposition,str2.length); 
                      if(checkMarchQ(patbackStr1,patbackStr2)) 
                    { 
                         경고(str1+''+ str2+"입력"); 
                      } 
                  } 
              } 
              else 
                { 
                    var patbeforeStr1 = str1.substring(0,position); 
                   var patbeforeStr2 = str2.substring(0,position); 
                   if(checkMarchQ(patbeforeStr1,patbeforeStr2)) 
                 { 
                    //alert(str1+'与'+str2+"前半부분분류"); 
                       var backposition = strX.length-position-1; 
                      if (backposition==0) 
                     { 
                       경고(str1+'与'+str2+"冲突"); 
                      } 
                     else 
                     { 
                          var patbackStr1 = str1.substring(str1.length-backposition,str1.length); 
                          var patbackStr2 = str2.substring(str2.length-backposition,str2.length); 
                          if(checkMarchQ(patbackStr1,patbackStr2)) 
                        { 
                             경고(str1+'与'+str2+"冲突"); 
                           } 
}
                                                                       ~ +str2+"충돌")
                             if(str1.length= =str2.length)
                { if(str1.substr (i,1)!='?' && str2.substr( i,1)!='?')
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