Parallel Query for MySQL with Shard-Query_MySQL

WBOY
풀어 주다: 2016-06-01 13:16:37
원래의
1241명이 탐색했습니다.

While Shard-Query can work over multiple nodes, this blog post focuses on using Shard-Query with a single node.  Shard-Query can add parallelism to queries which use partitionedtables.  Very large tables can often be partitioned fairly easily. Shard-Query can leverage partitioning to add paralellism, because each partition can be queried independently. Because MySQL 5.6 supports the partition hint, Shard-Query can add parallelism to any partitioning method (even subpartioning) on 5.6 but it is limited to RANGE/LIST partitioning methods on early versions.

The output from Shard-Query is from the commandline client, but you can use MySQL proxy to communicate with Shard-Query too.

In the examples I am going to use the schema from the Star Schema Benchmark.  I generated data for scale factor 10, which means about 6GB of data in the largest table. I am going to show a few different queries, and explain how Shard-Query executes them in parallel.

Here is the DDL for the lineorder table, which I will use for the demo queries:

CREATE TABLE IF NOT EXISTS lineorder( LO_OrderKey bigint not null, LO_LineNumber tinyint not null, LO_CustKey int not null, LO_PartKey int not null, LO_SuppKey int not null, LO_OrderDateKey int not null, LO_OrderPriority varchar(15), LO_ShipPriority char(1), LO_Quantity tinyint, LO_ExtendedPrice decimal, LO_OrdTotalPrice decimal, LO_Discount decimal, LO_Revenue decimal, LO_SupplyCost decimal, LO_Tax tinyint, LO_CommitDateKey int not null, LO_ShipMode varchar(10), primary key(LO_OrderDateKey,LO_PartKey,LO_SuppKey,LO_Custkey,LO_OrderKey,LO_LineNumber)) PARTITION BY HASH(LO_OrderDateKey) PARTITIONS 8;
로그인 후 복사

CREATETABLEIFNOTEXISTSlineorder

(

LO_OrderKeybigintnotnull,

LO_LineNumbertinyintnotnull,

LO_CustKeyintnotnull,

LO_PartKeyintnotnull,

LO_SuppKeyintnotnull,

LO_OrderDateKeyintnotnull,

LO_OrderPriorityvarchar(15),

LO_ShipPrioritychar(1),

LO_Quantitytinyint,

LO_ExtendedPricedecimal,

LO_OrdTotalPricedecimal,

LO_Discountdecimal,

LO_Revenuedecimal,

LO_SupplyCostdecimal,

LO_Taxtinyint,

LO_CommitDateKeyintnotnull,

LO_ShipModevarchar(10),

primarykey(LO_OrderDateKey,LO_PartKey,LO_SuppKey,LO_Custkey,LO_OrderKey,LO_LineNumber)

)PARTITIONBYHASH(LO_OrderDateKey)PARTITIONS8;

Notice that the lineorder table is partitioned by HASH(LO_OrderDateKey) into 8 partitions.  I used 8 partitions and my test box has 4 cores. It does not hurt to have more partitions than cores. A number of partitions that is two or three times the number of cores generally works best because it keeps each partition small, and smaller partitions are faster to scan. If you have a very large table, a larger number of partitions may be acceptable. Shard-Query will submit a query to Gearman for each partition, and the number of Gearman workers controls the parallelism.

The SQL for the first demo is:

SELECT COUNT(DISTINCT LO_OrderDateKey) FROM lineorder;
로그인 후 복사

SELECTCOUNT(DISTINCTLO_OrderDateKey)FROMlineorder;

Here is the explain from regular MySQL:

mysql> explain select count(distinct LO_OrderDateKey) from lineorder/G*************************** 1. row *************************** id: 1select_type: SIMPLEtable: lineorder type: indexpossible_keys: PRIMARYkey: PRIMARYkey_len: 25ref: NULL rows: 58922188Extra: Using index1 row in set (0.00 sec)
로그인 후 복사

mysql>explainselectcount(distinctLO_OrderDateKey)fromlineorder/G

***************************1.row***************************

          id:1

  select_type:SIMPLE

        table:lineorder

        type:index

possible_keys:PRIMARY

          key:PRIMARY

      key_len:25

          ref:NULL

        rows:58922188

        Extra:Usingindex

1rowinset(0.00sec)

So it is basically a full table scan. It takes a long time:

mysql> select count(distinct LO_OrderDateKey) from lineorder;+---------------------------------+| count(distinct LO_OrderDateKey) |+---------------------------------+|2406 |+---------------------------------+1 row in set (4 min 48.63 sec)
로그인 후 복사

mysql>selectcount(distinctLO_OrderDateKey)fromlineorder;

+---------------------------------+

|count(distinctLO_OrderDateKey)|

+---------------------------------+

|                            2406|

+---------------------------------+

1rowinset(4min48.63sec)

Shard-Query executes this query differently from MySQL. It sends a query to each partition, in parallel like the following queries:

Array([0] => SELECT LO_OrderDateKey AS expr_2839651562FROM lineorderPARTITION(p0)AS `lineorder` WHERE 1=1AND 1=1GROUP BY LO_OrderDateKey[1] => SELECT LO_OrderDateKey AS expr_2839651562FROM lineorderPARTITION(p1)AS `lineorder` WHERE 1=1AND 1=1GROUP BY LO_OrderDateKey[2] => SELECT LO_OrderDateKey AS expr_2839651562FROM lineorderPARTITION(p2)AS `lineorder` WHERE 1=1AND 1=1GROUP BY LO_OrderDateKey[3] => SELECT LO_OrderDateKey AS expr_2839651562FROM lineorderPARTITION(p3)AS `lineorder` WHERE 1=1AND 1=1GROUP BY LO_OrderDateKey[4] => SELECT LO_OrderDateKey AS expr_2839651562FROM lineorderPARTITION(p4)AS `lineorder` WHERE 1=1AND 1=1GROUP BY LO_OrderDateKey[5] => SELECT LO_OrderDateKey AS expr_2839651562FROM lineorderPARTITION(p5)AS `lineorder` WHERE 1=1AND 1=1GROUP BY LO_OrderDateKey[6] => SELECT LO_OrderDateKey AS expr_2839651562FROM lineorderPARTITION(p6)AS `lineorder` WHERE 1=1AND 1=1GROUP BY LO_OrderDateKey[7] => SELECT LO_OrderDateKey AS expr_2839651562FROM lineorderPARTITION(p7)AS `lineorder` WHERE 1=1AND 1=1GROUP BY LO_OrderDateKey)
로그인 후 복사
Array(

    [0]=>SELECTLO_OrderDateKeyASexpr_2839651562

FROMlineorder  PARTITION(p0)  AS`lineorder`  WHERE1=1  AND1=1  GROUPBYLO_OrderDateKey

    [1]=>SELECTLO_OrderDateKeyASexpr_2839651562

FROMlineorder  PARTITION(p1)  AS`lineorder`  WHERE1=1  AND1=1  GROUPBYLO_OrderDateKey

    [2]=>SELECTLO_OrderDateKeyASexpr_2839651562

FROMlineorder  PARTITION(p2)  AS`lineorder`  WHERE1=1  AND1=1  GROUPBYLO_OrderDateKey

    [3]=>SELECTLO_OrderDateKeyASexpr_2839651562

FROMlineorder  PARTITION(p3)  AS`lineorder`  WHERE1=1  AND1=1  GROUPBYLO_OrderDateKey

    [4]=>SELECTLO_OrderDateKeyASexpr_2839651562

FROMlineorder  PARTITION(p4)  AS`lineorder`  WHERE1=1  AND1=1  GROUPBYLO_OrderDateKey

    [5]=>SELECTLO_OrderDateKeyASexpr_2839651562

FROMlineorder  PARTITION(p5)  AS`lineorder`  WHERE1=1  AND1=1  GROUPBYLO_OrderDateKey

    [6]=>SELECTLO_OrderDateKeyASexpr_2839651562

FROMlineorder  PARTITION(p6)  AS`lineorder`  WHERE1=1  AND1=1  GROUPBYLO_OrderDateKey

    [7]=>SELECTLO_OrderDateKeyASexpr_2839651562

FROMlineorder  PARTITION(p7)  AS`lineorder`  WHERE1=1  AND1=1  GROUPBYLO_OrderDateKey

)

You will notice that there is one query for each partition.  Those queries will be sent to Gearman and executed in parallel by as many Gearman workers as possible (in this case 4.)  The output of the queries go into a coordinator table, and then another query does a final aggregation.  That query looks like this:

SELECT COUNT(distinct expr_2839651562) AS `count`FROM `aggregation_tmp_73522490`
로그인 후 복사

SELECTCOUNT(distinctexpr_2839651562)AS`count`

FROM`aggregation_tmp_73522490`

The Shard-Query time:

select count(distinct LO_OrderDateKey) from lineorder;Array([count ] => 2406)1 rows returnedExec time: 0.10923719406128
로그인 후 복사

selectcount(distinctLO_OrderDateKey)fromlineorder;

Array(

    [count]=>2406

)1rowsreturned

Exectime:0.10923719406128

That isn’t a typo, it really issub-secondcompared tominutesin regular MySQL.

This is because Shard-Query usesGROUP BYto answer this query and a loose index scanof the PRIMARY KEY is possible:

mysql> explain partitions SELECT LO_OrderDateKey AS expr_2839651562-> FROM lineorderPARTITION(p7)AS `lineorder` WHERE 1=1AND 1=1GROUP BY LO_OrderDateKey-> /G*************************** 1. row *************************** id: 1select_type: SIMPLEtable: lineorder partitions: p7 type: rangepossible_keys: PRIMARYkey: PRIMARYkey_len: 4ref: NULL rows: 80108Extra: Using index for group-by1 row in set (0.00 sec)
로그인 후 복사

mysql>explainpartitionsSELECTLO_OrderDateKeyASexpr_2839651562

    ->FROMlineorder  PARTITION(p7)  AS`lineorder`  WHERE1=1  AND1=1  GROUPBYLO_OrderDateKey

    ->/G

***************************1.row***************************

          id:1

  select_type:SIMPLE

        table:lineorder

  partitions:p7

        type:range

possible_keys:PRIMARY

          key:PRIMARY

      key_len:4

          ref:NULL

        rows:80108

        Extra:Usingindexforgroup-by

1rowinset(0.00sec)

Next another simple query will be tested, first on regular MySQL:

mysql> select count(*) from lineorder;+----------+| count(*) |+----------+| 59986052 |+----------+1 row in set (4 min 8.70 sec)
로그인 후 복사

mysql>selectcount(*)fromlineorder;

+----------+|count(*)|+----------+|59986052|+----------+

1rowinset(4min8.70sec)

Again, the EXPLAIN shows a full table scan:

mysql> explain select count(*) from lineorder/G*************************** 1. row *************************** id: 1select_type: SIMPLEtable: lineorder type: indexpossible_keys: NULLkey: PRIMARYkey_len: 25ref: NULL rows: 58922188Extra: Using index1 row in set (0.00 sec)
로그인 후 복사

mysql>explainselectcount(*)fromlineorder/G

***************************1.row***************************

          id:1

  select_type:SIMPLE

        table:lineorder

        type:index

possible_keys:NULL

          key:PRIMARY

      key_len:25

          ref:NULL

        rows:58922188

        Extra:Usingindex

1rowinset(0.00sec)

Now, Shard-Query can’t do anything special to speed up this query, except to execute it in parallel, similar to the first query:

[0] => SELECT COUNT(*) AS expr_3190753946FROM lineorder PARTITION(p0) AS `lineorder` WHERE 1=1 AND 1=1[1] => SELECT COUNT(*) AS expr_3190753946FROM lineorder PARTITION(p1) AS `lineorder` WHERE 1=1 AND 1=1[2] => SELECT COUNT(*) AS expr_3190753946FROM lineorder PARTITION(p2) AS `lineorder` WHERE 1=1 AND 1=1[3] => SELECT COUNT(*) AS expr_3190753946FROM lineorder PARTITION(p3) AS `lineorder` WHERE 1=1 AND 1=1...
로그인 후 복사

[0]=>SELECTCOUNT(*)ASexpr_3190753946

FROMlineorderPARTITION(p0)AS`lineorder`WHERE1=1AND1=1

[1]=>SELECTCOUNT(*)ASexpr_3190753946

FROMlineorderPARTITION(p1)AS`lineorder`WHERE1=1AND1=1

[2]=>SELECTCOUNT(*)ASexpr_3190753946

FROMlineorderPARTITION(p2)AS`lineorder`WHERE1=1AND1=1

[3]=>SELECTCOUNT(*)ASexpr_3190753946

FROMlineorderPARTITION(p3)AS`lineorder`WHERE1=1AND1=1

...

The aggregation SQL is similar, but this time the aggregate function is changed to SUM to combine the COUNT from each partition:

SELECT SUM(expr_3190753946) AS ` count `FROM `aggregation_tmp_51969525`
로그인 후 복사

SELECTSUM(expr_3190753946)AS`count`

FROM`aggregation_tmp_51969525`

And the query is quite a bit faster at 140.24 second compared with MySQL’s 248.7 second result:

Array([count ] => 59986052)1 rows returnedExec time: 140.24419403076
로그인 후 복사
Array(

[count]=>59986052

)1rowsreturned

Exectime:140.24419403076

Finally, I want to look at a more complex query that uses joins and aggregation.

mysql> explain select d_year, c_nation,sum(lo_revenue - lo_supplycost) as profitfrom lineorderjoin dim_dateon lo_orderdatekey = d_datekeyjoin customeron lo_custkey = c_customerkeyjoin supplieron lo_suppkey = s_suppkeyjoin parton lo_partkey = p_partkeywherec_region = 'AMERICA'and s_region = 'AMERICA'and (p_mfgr = 'MFGR#1'or p_mfgr = 'MFGR#2')group by d_year, c_nationorder by d_year, c_nation;+----+-------------+-----------+--------+---------------+---------+---------+--------------------------+------+---------------------------------+| id | select_type | table | type | possible_keys | key | key_len | ref| rows | Extra |+----+-------------+-----------+--------+---------------+---------+---------+--------------------------+------+---------------------------------+|1 | SIMPLE| dim_date| ALL| PRIMARY | NULL| NULL| NULL |5 | Using temporary; Using filesort ||1 | SIMPLE| lineorder | ref| PRIMARY | PRIMARY | 4 | ssb.dim_date.D_DateKey | 89 | NULL||1 | SIMPLE| supplier| eq_ref | PRIMARY | PRIMARY | 4 | ssb.lineorder.LO_SuppKey |1 | Using where ||1 | SIMPLE| customer| eq_ref | PRIMARY | PRIMARY | 4 | ssb.lineorder.LO_CustKey |1 | Using where ||1 | SIMPLE| part| eq_ref | PRIMARY | PRIMARY | 4 | ssb.lineorder.LO_PartKey |1 | Using where |+----+-------------+-----------+--------+---------------+---------+---------+--------------------------+------+---------------------------------+5 rows in set (0.01 sec)
로그인 후 복사

mysql>explainselectd_year,c_nation,  sum(lo_revenue-lo_supplycost)asprofit  fromlineorder  

joindim_date  onlo_orderdatekey=d_datekey  

joincustomer  onlo_custkey=c_customerkey  

joinsupplier  onlo_suppkey=s_suppkey  

joinpart  onlo_partkey=p_partkey  

where  c_region='AMERICA'  ands_region='AMERICA'  

and(p_mfgr='MFGR#1'  orp_mfgr='MFGR#2')  

groupbyd_year,c_nation  orderbyd_year,c_nation;

+----+-------------+-----------+--------+---------------+---------+---------+--------------------------+------+---------------------------------+

|id|select_type|table    |type  |possible_keys|key    |key_len|ref                      |rows|Extra                          |

+----+-------------+-----------+--------+---------------+---------+---------+--------------------------+------+---------------------------------+

|  1|SIMPLE      |dim_date  |ALL    |PRIMARY      |NULL    |NULL    |NULL                    |    5|Usingtemporary;Usingfilesort|

|  1|SIMPLE      |lineorder|ref    |PRIMARY      |PRIMARY|4      |ssb.dim_date.D_DateKey  |  89|NULL                            |

|  1|SIMPLE      |supplier  |eq_ref|PRIMARY      |PRIMARY|4      |ssb.lineorder.LO_SuppKey|    1|Usingwhere                    |

|  1|SIMPLE      |customer  |eq_ref|PRIMARY      |PRIMARY|4      |ssb.lineorder.LO_CustKey|    1|Usingwhere                    |

|  1|SIMPLE      |part      |eq_ref|PRIMARY      |PRIMARY|4      |ssb.lineorder.LO_PartKey|    1|Usingwhere                    |

+----+-------------+-----------+--------+---------------+---------+---------+--------------------------+------+---------------------------------+

5rowsinset(0.01sec)

Here is the query on regular MySQL:

mysql> select d_year, c_nation,sum(lo_revenue - lo_supplycost) as profitfrom lineorderjoin dim_dateon lo_orderdatekey = d_datekeyjoin customeron lo_custkey = c_customerkeyjoin supplieron lo_suppkey = s_suppkeyjoin parton lo_partkey = p_partkeywherec_region = 'AMERICA'and s_region = 'AMERICA'and (p_mfgr = 'MFGR#1'or p_mfgr = 'MFGR#2')group by d_year, c_nationorder by d_year, c_nation;+--------+---------------+--------------+| d_year | c_nation| profit |+--------+---------------+--------------+| 1992 | ARGENTINA | 102741829748 |...| 1998 | UNITED STATES |61345891337 |+--------+---------------+--------------+35 rows in set (11 min 56.79 sec)
로그인 후 복사

mysql>selectd_year,c_nation,  sum(lo_revenue-lo_supplycost)asprofit  fromlineorder  joindim_date  onlo_orderdatekey=d_datekey  joincustomer  onlo_custkey=c_customerkey  joinsupplier  onlo_suppkey=s_suppkey  joinpart  onlo_partkey=p_partkey  where  c_region='AMERICA'  ands_region='AMERICA'  and(p_mfgr='MFGR#1'  orp_mfgr='MFGR#2')  groupbyd_year,c_nation  orderbyd_year,c_nation;

+--------+---------------+--------------+

|d_year|c_nation      |profit      |

+--------+---------------+--------------+

|  1992|ARGENTINA    |102741829748|

...

|  1998|UNITEDSTATES|  61345891337|

+--------+---------------+--------------+

35rowsinset(11min56.79sec)

Again, Shard-Query splits up the query to run over each partition (I won’t bore you with the details) and it executes the query faster than MySQL, in 343.3 second compared to ~720:

Array([d_year] => 1998[c_nation] => UNITED STATES[profit] => 61345891337)35 rows returnedExec time: 343.29854893684
로그인 후 복사
Array(

    [d_year]=>1998

    [c_nation]=>UNITEDSTATES

    [profit]=>61345891337

)35rowsreturned

Exectime:343.29854893684

I hope you see how using Shard-Query can speed up queries without using sharding, on just a single server. All you really need to do is add partitioning.

You can get Shard-Query from GitHub at http://github.com/greenlion/swanhart-tools

Please note: Configure and install Shard-Query as normal, but simply use one node and set thecolumnoption (the shard column) to “nocolumn” or false, because you are not required to use a shard column if you are not sharding.

원천:php.cn
본 웹사이트의 성명
본 글의 내용은 네티즌들의 자발적인 기여로 작성되었으며, 저작권은 원저작자에게 있습니다. 본 사이트는 이에 상응하는 법적 책임을 지지 않습니다. 표절이나 침해가 의심되는 콘텐츠를 발견한 경우 admin@php.cn으로 문의하세요.
인기 튜토리얼
더>
최신 다운로드
더>
웹 효과
웹사이트 소스 코드
웹사이트 자료
프론트엔드 템플릿