javascript鼠标滑动评分控件完整实例_javascript技巧-JS 튜토리얼-php.cn

javascript鼠标滑动评分控件完整实例_javascript技巧

WBOY

풀어 주다： 2016-05-16 15:59:23

원래의

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本文实例讲述了javascript鼠标滑动评分控件。分享给大家供大家参考。具体实现方法如下：

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>javascript鼠标滑动控件</title>
<script type="text/javascript">
function ArrayIndexof(arr, inElement) {
  for (var i = 0; i < arr.length; i++) {
 if (arr[i] == inElement) {
   return i;
 }
  }
  return -1;
}
function GetTDS() {
  var tbl = document.getElementById("tblMain");
  var tds = tbl.getElementsByTagName("td");
  return tds;      
}
function iniEvent() {
  var tds = GetTDS();
  for (var i = 0; i < tds.length; i++) {
 td = tds[i];
 td.onmouseover = TdOnMouseOver;
  }
  var tbl = document.getElementById("tblMain");
  tbl.onmouseout = TableMouseOut;
}
function SetRating(tdTmp) {
  var tds = GetTDS();
  var index = ArrayIndexof(tds, tdTmp);
  for (var i = 0; i <= index; i++) {
 td = tds[i];
 td.innerHTML = "★";
  }
  for (var i = index + 1; i < tds.length; i++) {
 td = tds[i];
 td.innerHTML = "☆";
  }
}
function TdOnMouseOver() {
  SetRating(this);
}
//鼠标离开表格后自动清除
function TableMouseOut() {
  var tds = GetTDS();
  for (var i = 0; i < tds.length; i++) {
 td = tds[i];
 td.innerHTML = "☆";         
  }
}
</script>
</head>
<body onload="iniEvent()">
<table id="tblMain" border="1">
<tr>
  <td>☆</td>
  <td>☆</td>
  <td>☆</td>
  <td>☆</td>
  <td>☆</td>
</tr>
</table>
</body>
</html>

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希望本文所述对大家的javascript程序设计有所帮助。