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PHP日期函数date格式化UNIX时间的方法

WBOY
풀어 주다: 2018-09-27 15:56:12
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这篇文章主要介绍了PHP日期函数date格式化UNIX时间的方法,实例分析了php中date函数的使用技巧,需要的朋友可以参考下

本文实例讲述了PHP日期函数date格式化UNIX时间的方法。分享给大家供大家参考。具体分析如下:

日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出

使用到函数语法如下

string date (string $Format);
string date (string $Format, int $Time);
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下面是演示代码

<?php
echo "When this page was loaded,\n";
echo &#39;It was then &#39;, date (&#39;r&#39;), "\n";
echo &#39;The currend date was &#39;, date (&#39;F j, Y&#39;), "\n";
echo &#39;The currend date was &#39;, date (&#39;M j, Y&#39;), "\n";
echo &#39;The currend date was &#39;, date (&#39;m/d/y&#39;), "\n";
echo &#39;The currend date was the &#39;, date (&#39;jS \o\f M, Y&#39;), "\n";
echo &#39;The currend time was &#39;, date (&#39;g:i:s A T&#39;), "\n";
echo &#39;The currend time was &#39;, date (&#39;H:i:s O&#39;), "\n";
echo date (&#39;Y&#39;);
date (&#39;L&#39;)?(print &#39; is&#39;):(print &#39; is not&#39;);
echo " a leap year\n";
echo time (&#39;U&#39;), " seconds had elapsed since January 1, 1970.\n";
?>
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输出结果如下

It was then Sat, 26 Dec 2009 07:09:51 +0000
The currend date was December 26, 2009
The currend date was Dec 26, 2009
The currend date was 12/26/09
The currend date was the 26th of Dec, 2009
The currend time was 7:09:51 AM GMT
The currend time was 07:09:51 +0000
2009 is not a leap year
1261811391 seconds had elapsed since January 1, 1970.
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