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This document uses PHP Chinese website manual Release
(PHP 4, PHP 5, PHP 7)
ftp_size — 返回指定文件的大小
$ftp_stream
, string $remote_file
) ftp_size() 函数以字节返回远程文件
remote_file
的大小。如果指定文件不存在或发生错误,则返回
-1。有些 FTP 服务器可能不支持此特性。
Note:
获取成功返回文件大小,否则返回 -1。
ftp_stream
FTP 连接资源。
remote_file
远程文件。
执行成功返回文件大小,失败返回 -1。
Example #1 ftp_size() 例子
<?php
$file = 'somefile.txt' ;
// set up basic connection
$conn_id = ftp_connect ( $ftp_server );
// login with username and password
$login_result = ftp_login ( $conn_id , $ftp_user_name , $ftp_user_pass );
// get the size of $file
$res = ftp_size ( $conn_id , $file );
if ( $res != - 1 ) {
echo "size of $file is $res bytes" ;
} else {
echo "couldn't get the size" ;
}
//close the conntion
ftp_close ( $conn_id );
?>
[#1] gerben at gerbs dot net [2012-06-22 19:25:51]
To overcome the 2 GB limitation, the ftp_raw solution below is probably the nicest. You can also perform this command using regular FTP commands:
<?php
$response = ftp_raw($ftpConnection, "SIZE $filename");
$filesize = floatval(str_replace('213 ', '', $response[0]));
?>
[However, this] is insufficient for use on directories. As per RFC 3659 (http://tools.ietf.org/html/rfc3659#section-4.2), servers should return error 550 (File not found) if the command is issued on something else than a file, or if some other error occurred. For example, Filezilla indeed returns this string when using the ftp_raw command on a directory:
array(1) {
[0]=>
string(18) "550 File not found"
}
RFC 959 (http://tools.ietf.org/html/rfc959) dictates that the returned string always consists of exactly 3 digits, followed by 1 space, followed by some text. (Multi-line text is allowed, but I am ignoring that.) So it is probably better to split the string with substr, or even a regular expression.
<?php
$response = ftp_raw($ftp, "SIZE $filename");
$responseCode = substr($response[0], 0, 3);
$responseMessage = substr($response[0], 4);
?>
Or with a regular expression:
<?php
$response = ftp_raw($ftp, "SIZE $filename");
if (preg_match("/^(\\d{3}) (.*)$/", $response[0], $matches) == 0)
throw new Exception("Unable to parse FTP reply: ".$response[0]);
list($response, $responseCode, $responseMessage) = $matches;
?>
You could then decide to assume that response code '550' means that it's a directory. I guess that's just as 'dangerous' as assuming that ftp_size -1 means that it's a directory.
[#2] ibeono at gmail dot com [2011-07-28 04:19:09]
If you experience troubles with size of large file then you can use ftp_rawlist function and parse it result
[#3] bluerain [at] telenet [dot] be [2009-07-10 01:41:18]
To overcome the 2GB file size limit, you can open your own socket to get the file size of a large file. Quick and dirty script:
<?php
$socket=fsockopen($hostName, 21);
$t=fgets($socket, 128);
fwrite($socket, "USER $myLogin\r\n");
$t=fgets($socket, 128);
fwrite($socket, "PASS $myPass\r\n");
$t=fgets($socket, 128);
fwrite($socket, "SIZE $fileName\r\n");
$t=fgets($socket, 128);
$fileSize=floatval(str_replace("213 ","",$t));
echo $fileSize;
fwrite($socket, "QUIT\r\n");
fclose($socket);
?>
[#4] miccots at gmail dot com [2007-10-30 01:55:31]
2 adams[AT]techweavers[DOT]net:
To get a size of large file (f. ex.: 3.2 Gb) you have to format the result returned by ftp_size():
$size = sprintf ("%u", ftp_size($connection, $file_name));
So you can get the real size of big files. But this method is not good for checking is this a dir (when ftp_size() returns -1).
[#5] C_Muller [2007-07-21 15:42:50]
For checking if a certain folder exists try using ftp_nlist() function to get a directory list in array. By using in_array('foldername') you can find out if it is there or not.
[#6] chuck at t8design dot com [2006-05-23 09:54:51]
note that project_t4 at hotmail dot com's example above doesn't work in general, though it works on his Win2K/Apache server; as far as I can tell there is no way to check over ftp whether a directory exists. This function's behavior given a directory name seems to be at least somewhat dependent on your OS, web server, or ftp server, I don't know which.
[#7] adams[AT]techweavers[DOT]net [2005-06-21 14:30:51]
Well this function is nice but if you have files larger then 2.1Gb or 2.1 Billion Bytes you cannot get its size.
[#8] [2004-09-28 18:10:21]
To get a dirsize recursive you can use this simple function:
<?php # copyright by fackelkind | codeMaster
function getRecDirSize ($connection, $dir){
$temp = ftp_rawlist ($connection, "-alR $dir");
foreach ($temp as $file){
if (ereg ("([-d][rwxst-]+).* ([0-9]) ([a-zA-Z0-9]+).* ([a-zA-Z0-9]+).* ([0-9]*) ([a-zA-Z]+[0-9: ]*[0-9]) ([0-9]{2}:[0-9]{2}) (.+)", $file, $regs)){
$isdir = (substr ($regs[1],0,1) == "d");
if (!$isdir)
$size += $regs[5];
}
}
return $size;
}
$dirSize = getRecDirSize ($conID, "/");
?>
[#9] project_t4 at hotmail dot com [2004-03-18 11:03:14]
Just to let people out there know, on my windows 2000 server running Apache and php i was returned 0 not -1 for directories.
foreach ($dir_list as $item)
{
if(ftp_size($conn_id, $item) == "0")
{
echo "<br>Directory:: ".$item;
} else {
echo "<br>File:: ".$item;
}
}
This outputs a list of the remote directory and indicates which items are directories and which are files.
[#10] nicke_ at at_h9k dot com [2003-10-03 18:48:31]
This will return the filesize on remote host and the size if you download it in FTP_BINARY mode. If you are using FTP_ASCII in ftp_get() the size can be changed.
[#11] victor59 at yahoo dot com dot hk [2002-12-23 01:44:14]
$file= 'filename with space.txt';
$size = ftp_size($this->ftp, urldecode($file) );
this one can correctly return the size
otherwize, it always return -1