fungsi js yang menukar nombor kepada kemahiran RMB expressions_javascript huruf besar

Terdapat banyak cara untuk menukar nombor kepada RMB huruf besar Contoh ini memperkenalkan cara menggunakan js untuk melengkapkannya. Lihat kod pelaksanaan di bawah

function changeNumMoneyToChinese(money) {
  var cnNums = new Array("零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"); //汉字的数字
  var cnIntRadice = new Array("", "拾", "佰", "仟"); //基本单位
  var cnIntUnits = new Array("", "万", "亿", "兆"); //对应整数部分扩展单位
  var cnDecUnits = new Array("角", "分", "毫", "厘"); //对应小数部分单位
  var cnInteger = "整"; //整数金额时后面跟的字符
  var cnIntLast = "元"; //整型完以后的单位
  var maxNum = 999999999999999.9999; //最大处理的数字
  var IntegerNum; //金额整数部分
  var DecimalNum; //金额小数部分
  var ChineseStr = ""; //输出的中文金额字符串
  var parts; //分离金额后用的数组，预定义
  if (money == "") {
    return "";
  }
  money = parseFloat(money);
  if (money >= maxNum) {
    alert('超出最大处理数字');
    return "";
  }
  if (money == 0) {
    ChineseStr = cnNums[0] + cnIntLast + cnInteger;
    return ChineseStr;
  }
  money = money.toString(); //转换为字符串
  if (money.indexOf(".") == -1) {
    IntegerNum = money;
    DecimalNum = '';
  } else {
    parts = money.split(".");
    IntegerNum = parts[0];
    DecimalNum = parts[1].substr(0, 4);
  }
  if (parseInt(IntegerNum, 10) > 0) { //获取整型部分转换
    var zeroCount = 0;
    var IntLen = IntegerNum.length;
    for (var i = 0; i < IntLen; i++) {
      var n = IntegerNum.substr(i, 1);
      var p = IntLen - i - 1;
      var q = p / 4;
      var m = p % 4;
      if (n == "0") {
        zeroCount++;
      } else {
        if (zeroCount > 0) {
          ChineseStr += cnNums[0];
        }
        zeroCount = 0; //归零
        ChineseStr += cnNums[parseInt(n)] + cnIntRadice[m];
      }
      if (m == 0 && zeroCount < 4) {
        ChineseStr += cnIntUnits[q];
      }
    }
    ChineseStr += cnIntLast;
    //整型部分处理完毕
  }
  if (DecimalNum != '') { //小数部分
    var decLen = DecimalNum.length;
    for (var i = 0; i < decLen; i++) {
      var n = DecimalNum.substr(i, 1);
      if (n != '0') {
        ChineseStr += cnNums[Number(n)] + cnDecUnits[i];
      }
    }
  }
  if (ChineseStr == '') {
    ChineseStr += cnNums[0] + cnIntLast + cnInteger;
  } else if (DecimalNum == '') {
    ChineseStr += cnInteger;
  }
  return ChineseStr;

}