SQL Server sendiri tidak mengandungi fungsi LISTAGG, tetapi fungsi yang serupa boleh dicapai melalui pelbagai kaedah.
<code class="language-sql">SELECT FieldA, GROUP_CONCAT(FieldB ORDER BY FieldB SEPARATOR ',') AS FieldBs FROM TableName GROUP BY FieldA ORDER BY FieldA;</code>
<code class="language-sql">SELECT FieldA, LISTAGG(FieldB, ',') WITHIN GROUP (ORDER BY FieldB) AS FieldBs FROM TableName GROUP BY FieldA ORDER BY FieldA;</code>
<code class="language-sql">SELECT FieldA, STRING_AGG(FieldB, ',' ORDER BY FieldB) AS FieldBs FROM TableName GROUP BY FieldA ORDER BY FieldA;</code>
SQL Server >= 2017 & Azure SQL
<code class="language-sql">SELECT FieldA, STRING_AGG(FieldB, ',') WITHIN GROUP (ORDER BY FieldB) AS FieldBs FROM TableName GROUP BY FieldA ORDER BY FieldA;</code>
SQL Server (versi lain)
Untuk kebolehbacaan dan kebolehselenggaraan kod, ungkapan jadual biasa (CTE) digunakan di sini:
<code class="language-sql">WITH CTE_TableName AS ( SELECT FieldA, FieldB FROM TableName ) SELECT t0.FieldA, STUFF( ( SELECT ',' + t1.FieldB FROM CTE_TableName t1 WHERE t1.FieldA = t0.FieldA ORDER BY t1.FieldB FOR XML PATH('') ), 1, LEN(','), '' ) AS FieldBs FROM CTE_TableName t0 GROUP BY t0.FieldA ORDER BY FieldA;</code>
Apabila pengisihan diperlukan, anda perlu menggunakan CTE atau subquery
<code class="language-sql">WITH CTE_TableName AS ( SELECT FieldA, FieldB FROM TableName ORDER BY FieldA, FieldB ) SELECT FieldA, GROUP_CONCAT(FieldB, ',') AS FieldBs FROM CTE_TableName GROUP BY FieldA ORDER BY FieldA;</code>
Apabila tiada pengisihan diperlukan
<code class="language-sql">SELECT FieldA, GROUP_CONCAT(FieldB, ',') AS FieldBs FROM TableName GROUP BY FieldA ORDER BY FieldA;</code>
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