php 合龙两个二维数组

php 合并两个二维数组
按时间排序的

<br /><br />$data1 = array(<br /><br />    [0] => array(<br />        times => '2012-10-10',<br />        type =>0,<br />        num =>100<br />    ），<br /><br />    [1] => array(<br />        times => '2012-10-11',<br />        type =>0,<br />        num =>103<br />    ），<br /><br />  ....<br />       <br />)<br /><br />$data2 = array(<br /><br />    [0] => array(<br />        times => '2012-10-10',<br />        type =>1,<br />        num =>400<br />    ），<br /><br />    [1] => array(<br />        times => '2012-10-11',<br />        type =>1,<br />        num =>403<br />    ），<br /><br />  ....<br />       <br />)<br /><br />

两个数组times 是一样的，怎么把它们合并成

<br />$data = array(<br /><br />    [0] => array(<br />        times => '2012-10-10',<br />        type =>0,<br />        num =>100<br />        type =>1,<br />        num =>400<br />    ），<br /><br />    [1] => array(<br />        times => '2012-10-11',<br />        type =>0,<br />        num =>103<br />        type =>1,<br />        num =>403<br />    ），<br /><br />  ....<br />       <br />)<br />

求教

------解决方案--------------------
楼主，就冲你那0的结贴率，呵呵。

<br /> $date=array(array("time"=>"2012-11-10","type0"=>0,"num0"=>100),array("time"=>"2012-11-11","type0"=>0,"num0"=>103));<br /> $date1=array(array("time"=>"2012-11-10","type1"=>1,"num1"=>105),array("time"=>"2012-11-11","type1"=>1,"num1"=>120));<br /> $cnt=count($date);<br /> for($i=0;$i<$cnt;$i++){<br />	$date2[$i]=array_merge($date[$i],$date1[$i]);<br />}<br /> echo "<pre class="brush:php;toolbar:false">";<br /> print_r($date);<br /> print_r($date1);<br /> print_r($date2);<br /> echo "

";
//结果如下
Array
(
    [0] => Array
        (
            [time] => 2012-11-10
            [type0] => 0
            [num0] => 100
        )