PHP 数据库解决方法

PHP 数据库
数组:Array ( [0] => Array ( [id] => 42 ) [1] => Array ( [id] => 49 ) [2] => Array ( [id] => 50 ) [3] => Array ( [id] => 51 ) [4] => Array ( [id] => 52 ) ) ?，这里为数据表里的id字段，怎样根据这些id，修改每一个id对应的另一个字段count？第一个id的count加1，第二个id对应的加2，第三个加3.。。。。这样循环下去
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$arr = array ( 0 => array ( 'id' => 42 ) ,1 => array ( 'id' => 49 ), 2 => array ( 'id' => 50 ), 3 => array ( 'id' => 51 ), 4 => array ( 'id' => 52 ) );<br />foreach ($arr as $key => $value) {<br />	$sql = "update tableName set count = count + ".($key+1)." where id = ".$value['id'];<br />	mysql_query($sql);<br />}

------解决方案--------------------

$ar = array ( 0 => array ( 'id' => 42 ) ,1 => array ( 'id' => 49 ), 2 => array ( 'id' => 50 ), 3 => array ( 'id' => 51 ), 4 => array ( 'id' => 52 ) );<br />$s = join(',', array_map('current', $ar));<br />$sql = "update tbl_name set count=count+find_inset(id,'$s')";<br />mysql_query($sql);<br />