PHP怎么接受ajax的post 表单并分行保存TXT呢

求助 PHP如何接受ajax的post 表单并分行保存TXT呢
JS代码如下

function SubmitApply() {<br />    var form = Global.GetElement("#submitForm");<br />    var UserName = Global.GetElement(form, 'input[name="Name"]').value;<br />    var Mobile = Global.GetElement(form, 'input[name="Tel"]').value;<br />    var Position = Global.GetElement(form, 'input[name="Position"]').value;<br />    var Company = Global.GetElement(form, 'input[name="Company"]').value;<br />    var ActId = Global.GetElement(form, 'input[name="Actid"]').value;<br />    if (Global.IsNullOrWhitesapce(UserName)) {<br />        Global.Tip.TipError("姓名必须填写");<br />        return;<br />    }<br />    if (Global.IsNullOrWhitesapce(Mobile)) {<br />        Global.Tip.TipError("手机必须填写");<br />        return;<br />    }<br />    if (/^1[3|4|5|8][0-9]\d{4,8}$/.test(Mobile) == false) {<br />        Global.Tip.TipError("手机格式不正确");<br />        return;<br />    }<br />    var ajaxRequest = new HttpAjaxRequest();<br />    ajaxRequest.ajax({<br />        dataType: 'json',<br />        url: '',<br />        data: { name: UserName, mobile: Mobile, companyname: Company, position: Position, actid: ActId },<br />        successed: OnSubmitAppplySuccesse,<br />        error: function () {<br />            Global.Tip.TipError('提交失败!');<br />            GlobalPlayer.DisableNext();<br />        }<br />    });<br />}<br /><br />/**<br /> * 名称：申请提交成功<br /> */<br />function OnSubmitAppplySuccesse(data) {<br />    if (data.Code == 0) {<br />        Global.Tip.TipMessage('提交成功!');<br />        var form = Global.GetElement("#submitForm");<br />        GlobalPlayer.EnableNext();<br />        GlobalPlayer.PlayNext();<br />        form.reset();<br />    } else {<br />        Global.Tip.TipError('提交失败!' + data.Message);<br />        GlobalPlayer.DisableNext();<br />    }<br />}

哪个好人帮我写个完整的PHP接受源码吧 本人PHP小白（已哭晕）
------解决思路----------------------
在贴吧看到你了。。


ajaxRequest.ajax({
dataType: 'json',
url: './save_to_txt.php',
data: { name: UserName, mobile: Mobile, companyname: Company, position: Position, actid: ActId },
successed: OnSubmitAppplySuccesse,
error: function () {
Global.Tip.TipError('提交失败!');
GlobalPlayer.DisableNext();
}
});


save_to_txt.php:

<br />$name = $_POST['name'];<br />$mobile = $_POST['mobile'];<br />$companyname = $_POST['companyname'];<br />$actid = $_POST['actid'];<br />$position = $_POST['position'];<br /> $str =$name. "\n".$mobile."\n".$companyname."\n".$actid."\n".$position;<br />$h = fopen('./t.txt','w');<br />fwrite($h,$str);<br />fclose($h);<br />

------解决思路----------------------
你没有指定工作方式，默认应该的 GET
用 $_POST 当然收不到数据