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PHP+MySQL实现的简单投票系统实例_php技巧

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Lepaskan: 2016-05-16 19:58:15
asal
1676 orang telah melayarinya

本文实例讲述了PHP+MySQL实现的简单投票系统。分享给大家供大家参考,具体如下:

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<html>

<head><title>手机系统调查问卷</title>

<style type="text/css">

<!--

span{

  width:600px;

  height:100px;

  background-color:write;

  postion:relative;

  border:1px #cccccc solid;

}

div{

  width:60px;

  height:1px;

  background-color:blue;

  postion:absolute;

  bottom:0;

}

-->

</style>

</head>

<body>

你现在使用的手机是什么系统?

<form id="form1" method="POST" action="count.php">

<input type="radio" name="phone" value="1"> Android安卓

<input type="radio" name="phone" value="2"> Symbian塞班

<br>

<input type="radio" name="phone" value="3"> iphone苹果

<input type="radio" name="phone" value="4"> Google谷歌

<br>

<input type="radio" name="phone" value="5"> Winphone微软

<input type="radio" name="phone" value="6"> 其它

<br>

<input type="submit" value="提交">

</form>

<span>

当前票数:<br>

<&#63;php

include 'connect.php';

$sql="select answer from countone";

$rs=mysql_query($sql);

$total=mysql_num_rows($rs);

$sql="select * from countone where answer=1";

$rs=mysql_query($sql);

$android=mysql_num_rows($rs);

$sql="select * from countone where answer=2";

$rs=mysql_query($sql);

$symbian=mysql_num_rows($rs);

$sql="select * from countone where answer=3";

$rs=mysql_query($sql);

$iphone=mysql_num_rows($rs);

$sql="select * from countone where answer=4";

$rs=mysql_query($sql);

$google=mysql_num_rows($rs);

$sql="select * from countone where answer=5";

$rs=mysql_query($sql);

$winphone=mysql_num_rows($rs);

$sql="select * from countone where answer=6";

$rs=mysql_query($sql);

$other=mysql_num_rows($rs);

&#63;>

<table border="0">

<th>android</th><th>Symbian</th><th>iphone</th><th>Google</th><th>winphone</th><th>other</th>

<tr>

<td><&#63;php echo $android &#63;>票</td>

<td><&#63;php echo $symbian &#63;>票</td>

<td><&#63;php echo $iphone &#63;>票</td>

<td><&#63;php echo $google &#63;>票</td>

<td><&#63;php echo $winphone &#63;>票</td>

<td><&#63;php echo $other &#63;>票</td>

</tr>

<tr>

<td><&#63;php for ($i=1;$i<=$android/$total+1;$i=$i+0.1){  echo "<div></div>"; } &#63;></td>

<td><&#63;php for ($i=1;$i<=$symbian/$total+1;$i=$i+0.1){  echo "<div></div>"; } &#63;></td>

<td><&#63;php for ($i=1;$i<=$iphone/$total+1;$i=$i+0.1){  echo "<div></div>"; } &#63;></td>

<td><&#63;php for ($i=1;$i<=$google/$total+1;$i=$i+0.1){  echo "<div></div>"; } &#63;></td>

<td><&#63;php for ($i=1;$i<=$winphone/$total+1;$i=$i+0.1){ echo "<div></div>"; } &#63;></td>

<td><&#63;php for ($i=1;$i<=$other/$total+1;$i=$i+0.1){ echo "<div></div>"; } &#63;></td>

</tr>

</table>

</span>

</body>

</html>

Salin selepas log masuk

写的有点啰嗦,有点笨但很实用

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<&#63;php

include 'connect.php';

$name=$_POST['phone'];

$sql="insert into countone values(null,$name,now(),null)";

mysql_query($sql);

&#63;>

<script type="text/javascript">

 alert ("投票成功!");

 location="question.php";

</script>

Salin selepas log masuk

链接mysql:

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<&#63;php

mysql_connect("localhost","root","");

mysql_select_db("vote");

mysql_query("set names utf8");

&#63;>

Salin selepas log masuk

更多关于PHP相关内容感兴趣的读者可查看本站专题:《php面向对象程序设计入门教程》、《php字符串(string)用法总结》、《php+mysql数据库操作入门教程》及《php常见数据库操作技巧汇总

希望本文所述对大家PHP程序设计有所帮助。

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