css能否绘制树形关系图？_html/css_WEB-ITnose-html tutorial-php.cn

css能否绘制树形关系图？_html/css_WEB-ITnose

WBOY

Lepaskan： 2016-06-24 12:12:45

asal

2205 orang telah melayarinya

如题,效果如下

回复讨论(解决方案)

找美工做图片吧

要么做图片，打热点
可以 canvas，flash VML 来做， js动态生成很多点来画线，效率低。

写了个js生成点画直线的，楼主参考下

<!DOCTYPE HTML><html>    <head>        <meta charset="gb2312" />        <title></title>        <style>            .point {                position:absolute;                width:1px; height:1px; overflow:hidden;                background:#000;            }            .col {                position:absolute; left:300px; top:100px;                font-size:20px; font-weight:bold; text-align:center;            }            .right {                left:500px;            }            p {                width:20px;                border:1px solid red;            }        </style>    </head>    <body>        <div class="col">            <p>a</p>            <p>c</p>            <p>b</p>        </div>        <div class="col right">            <p>B</p>            <p>A</p>            <p>C</p>        </div>                <script>            var x = [];            var y = [];            document.onclick = function(e){                    e = window.event || e;                var tx = e.clientX;                var ty = e.clientY;                x.push(tx);                y.push(ty);                //console.log( x );                //console.log( y );                                if( x.length == 2 && y.length == 2 ){                    createLine(x[0], y[0], x[1], y[1]);                    x.length = 0;                    y.length = 0;                }                        }            function point(x, y){                var div = document.createElement('div');                div.style.left = x + 'px';                div.style.top = y + 'px';                div.className = 'point';                document.body.appendChild(div);            }                                    function createLine(x1,y1,x2,y2){                var tmp, x, y;                if(x1 >= x2){                    tmp = x1;                    x1 = x2;                    x2 = tmp;                    tmp = y1;                    y1 = y2;                    y2 = tmp;                        }                for(var i = x1 ; i < x2; i++){                    x = i;                    y = (y2 - y1)/(x2 - x1)*(x - x1)+y1;                    point(x,y);                }            }             </script>    </body></html>

Salin selepas log masuk

?????,?主?考下:
?用鼠???名?展??????

nbsp;html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

Organization

<script> <br /> function bluring(){ <br /> if(event.srcElement.tagName=="A"||event.srcElement.tagName=="IMG") document.body.focus(); <br /> } <br /> document.onfocusin=bluring; <br /> </script>

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  - 科室
    - 一组
    - 二组
  - 布兰妮
    - A组
    - B组
      - A组
      - B组
      - C组
    - C组
  - 强仁
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