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python排序sort()与sorted()

高洛峰
Lepaskan: 2017-02-13 17:29:58
asal
1607 orang telah melayarinya

应用举例:

1.按照字母表输出一个序列

2.对记录的多个字段排序等

常用排序函数:

sort()

sorted()

比较:

1.sorted()应用范围更广

sorted(iterable[, cmp[, key[, reverse]]])

s.sorted([cmp[, key[, reverse]]])

示例:

>>> persons = [{'name':'Jon','age': 32}, {'name':'Alan','age': 50}, {'name': 'Bob', 'age':23}]
>>> sorted(persons, key=lambda x: (x['name'], -x['age']))
[{'age': 50, 'name': 'Alan'}, {'age': 23, 'name': 'Bob'}, {'age': 32, 'name': 'Jon'}]

sorted()可用于任意可迭代对象,sort()一般作用于列表

>>> a = (1,2,4,2,3)
>>> a.sort()
Traceback (most recent call last):
 File "", line 1, in
AttributeError: 'tuple' object has no attribute 'sort'
>>> sorted(a)
[1, 2, 2, 3, 4]

 

2.sorted()返回排序后的列表,原列表不变,sort()直接修改原有列表。

sort()因为不需要复制原有列表,消耗内存少,效率高

>>> a=['1',1,'a',3,7,'n']
>>> sorted(a)
[1, 3, 7, '1', 'a', 'n']
>>> a
['1', 1, 'a', 3, 7, 'n']
>>> a.sort()
>>> a
[1, 3, 7, '1', 'a', 'n']

 

3.对于sort()和sorted()函数,传入参数key比参数cmp效率高。cmp传入的函数在整个排序过程中多次调用,开销大;key针对每个元素仅作一次处理。

>>> from timeit import Timer
>>> Timer(stmt="sorted(xs,key=lambda x:x[1])",setup="xs=range(100);xs=zip(xs,xs);").timeit(10000)
0.35391712188720703
>>> Timer(stmt="sorted(xs,cmp=lambda a,b: cmp(a[1],b[1]))",setup="xs=range(100);xs=zip(xs,xs);").timeit(10000)
0.4931659698486328

 

4.sorted()可以对多种数据结构排序

字典:

将phonebook的电话号按数字大小排序

>>> phonebook = {'Linda':'7750','Bob':'9345','Carol':'5834'}
>>> from operator import itemgetter
>>> sorted_pb = sorted(phonebook.iteritems(),key=itemgetter(1))
>>> sorted_pb
[('Carol', '5834'), ('Linda', '7750'), ('Bob', '9345')]

多维list:

对成绩、等级多字段排序

>>> from operator import itemgetter
>>> gameresult = [['Bob',95.00,'A'],['Alan',86.0,'C'],['Mandy',82.5,'A'],['Rob',86,'E']]
>>> sorted(gameresult, key=itemgetter(2, 1))
[['Mandy', 82.5, 'A'], ['Bob', 95.0, 'A'], ['Alan', 86.0, 'C'], ['Rob', 86, 'E']]

字典中混合list:

>>> mydict = {'Li':['M',7],
...           'Zhang': ['E',2],
...            'Wang':['p',3],
...           'Du':['C',2]}
>>> from operator import itemgetter
>>> sorted(mydict.iteritems(),key=lambda(k,v):operator.itemgetter(1)(v))
[('Zhang', ['E', 2]), ('Du', ['C', 2]), ('Wang', ['p', 3]), ('Li', ['M', 7])]

 

List中混合字典:

对多个key值rating和name排序

>>> gameresult = [{"name":"Bob","wins":10,"losses":3,"rating":75.00},
...               {"name":"David","wins":3,"loses":5,"rating":57.00}]
>>> from operator import itemgetter
>>> sorted(gameresult,key=itemgetter("rating","name"))
[{'wins': 3, 'rating': 57.0, 'name': 'David', 'loses': 5}, {'wins': 10, 'losses': 3, 'name': 'Bob', 'rating': 75.0}]
>>>

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