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Ajax入门实例

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Lepaskan： 2018-06-29 14:53:47

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Ajax入门实例

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Ajax入门</title>
</head>
<body>
<form action="api/check.php" method="post">
<fieldset>
<legend>用户登录</legend>
<p>
<label for="email">邮箱:</label>
<input type="email" name="email" id="email">
</p>
<p>
<label for="password">邮箱:</label>
<input type="password" name="password" id="password">
</p>
<p><button>登录</button>
<span id="tips" style="font-size:1.2em;font-weight: bolder;color:red"></span></p>
<!-- 取消原生提交动作 -->
<!-- <p><button type="button">登录</button></p> -->
</fieldset>
</form>
</body>
</html>
<script type="text/javascript">
var btn = document.getElementsByTagName(&#39;button&#39;)[0]
btn.onclick = function () {
//获取用户提交的数据
var email = document.getElementById(&#39;email&#39;).value
var password = document.getElementById(&#39;password&#39;).value
//将用户数据组装成查询字符串
var data = &#39;email=&#39;+email+&#39;&password=&#39;+password
//1.创建xhr对象
var xhr = new XMLHttpRequest()
//2.事件监听
xhr.onreadystatechange = function (){
//5.设置回调函数
if (xhr.readyState == 4 && xhr.status == 200) {
//dom操作
var tips = document.getElementById(&#39;tips&#39;)
if (xhr.responseText == &#39;1&#39;) {
tips.innerHTML = &#39;登录成功,正在跳转中...&#39;
setTimeout(function(){
location.href = &#39;api/index.php&#39;
},2000)
} else {
tips.innerHTML = &#39;邮箱或密码错误,请重新输入&#39;
document.getElementById(&#39;email&#39;).focus()
setTimeout("tips.innerHTML = &#39;&#39;",2000)
}
}
}
//3.建立连接
xhr.open(&#39;POST&#39;,&#39;api/user.php?m=login&#39;,true)
//4.发送数据
xhr.setRequestHeader(&#39;Content-Type&#39;,&#39;application/x-www-form-urlencoded&#39;)
xhr.send(data)
return false  //禁止原按钮的提交行为
}
</script>

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