Gunakan HAVING untuk mencari semua lajur yang nama lajurnya lebih panjang daripada 5. Ini akan menghasilkan output berikut -
+-------------------+-------------------------+ | TABLE_NAME | COLUMN_NAME | +-------------------+-------------------------+ | DemoTable | UserId | | DemoTable | EndDate | | DemoTable | StartDate | | DemoTable | StudentFavouriteSubject | | DemoTable | StudentFirstName | | DemoTable | StudentId | | DemoTable | ShippingDate | | DemoTable | Number | | DemoTable | Value1 | | DemoTable | Value2 | | DemoTable | ArrivalDate | | DemoTable | ShippingDate | | DemoTable | UserAge | | DemoTable | UserId | | DemoTable | UserName | | DemoTable | CustomerId | | DemoTable | CustomerValue | | DemoTable | UserId | | DemoTable | UserMailId | | DemoTable | FirstName | | DemoTable | Number | | DemoTable | isMarried | | DemoTable | Number | | DemoTable | FruitName | | DemoTable | FruitPrice | | DemoTable | CustomerAllProductPrice | | DemoTable | CustomerId | | DemoTable | CustomerName | | DemoTable | UserId | | DemoTable | UserScore | | DemoTable | StudentAge | | DemoTable | StudentCountryName | | DemoTable | StudentFirstName | | DemoTable | StudentId | | DemoTable | StudentLastName | | DemoTable | FirstName | | DemoTable | Arrivaldatetime | | DemoTable | Amount | | DemoTable | Number | | DemoTable | Number | | DemoTable | FirstName | | DemoTable | CustomerId | | DemoTable | CustomerPrice | | DemoTable | CustomerProductName | | DemoTable | CustomerProductQuantity | | DemoTable | Value1 | | DemoTable | Value2 | | DemoTable | FirstName | | DemoTable | LastName | | DemoTable | UserId | | DemoTable | MonthNumber | | DemoTable | YearNumber | | insertcurrentdate | currentDate | | student | first_name | | student | last_name | +-------------------+-------------------------+ 55 rows in set (0.01 sec)
Atas ialah kandungan terperinci Bagaimana untuk mencari semua lajur dengan panjang nama lajur lebih besar daripada 5 dalam MySQL?. Untuk maklumat lanjut, sila ikut artikel berkaitan lain di laman web China PHP!