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Dokumen ini menggunakan Manual laman web PHP Cina Lepaskan
(PHP 4 >= 4.3.0, PHP 5)
odbc_data_source — Returns information about a current connection
$connection_id
, int $fetch_type
)This function will return the list of available DSN (after calling it several times).
connection_id
ODBC 连接标识符,详见 odbc_connect() 。
fetch_type
The fetch_type
can be one of two constant types:
SQL_FETCH_FIRST
, SQL_FETCH_NEXT
.
Use SQL_FETCH_FIRST
the first time this function is
called, thereafter use the SQL_FETCH_NEXT
.
Returns FALSE
on error, and an array upon success.
[#1] critmas at hotmail dot com [2005-02-25 11:53:11]
Thank you Angelo for point out the code. Though the function doesn't really do what it is supposed to. It returns the entire list of ODBC DSNs.
If you really are looking to get the server type based on just the ODBC, username and password in an environment where the application needs to be aware of different types of databases, use the following code:
$link2 = odbc_connect($dsn , $DBUser, $DBPwd ) or die(odbc_errormsg() );
$result = @odbc_data_source( $link2, SQL_FETCH_FIRST );
while($result)
{
if (strtolower($dsn) == strtolower($result['server'])) {
echo $result['description'] . "<br>\n";
break;
}
else
$result = @odbc_data_source( $link2, SQL_FETCH_NEXT );
}
odbc_close($link2);
// Hope it saves your precious time
[#2] angelo [at] spaceblue [dot] com [2003-12-01 10:51:29]
// Example usage:
// Connect to a ODBC database that exists on your system
$link = odbc_connect("some_dsn_name", "user", "password") or die(odbc_errormsg() );
$result = @odbc_data_source( $link, SQL_FETCH_FIRST );
while($result)
{
echo "DSN: " . $result['server'] . " - " . $result['description'] . "<br>\n";
$result = @odbc_data_source( $link, SQL_FETCH_NEXT );
}
odbc_close($link);