javascript - Bagaimana untuk melaksanakan operasi ini dalam js, get(obj,'k1','k2','k3').then((v)=>console.log(v))

Question

Serupa dengan kod di bawah

get(obj,'k1','k2','k3')
    .then((v)=>console.log(v))
    .else(()=>console.log('值为空'));

Laksanakan fungsi kod berikut

if(obj && obj.k1 && obj.k1.k2 && obj.k1.k2.k3){
    console.log(obj.k1.k2.k3);
}else{
    console.log('值为空')
}

Answer 1

Menggunakan pelaksanaan es6+promise

// 功能实现
function get(obj, ...props) {
  // 检查该对象是否拥有某个属性
  function hasProp(obj, prop) {
    return !!obj[prop]
  }

  return new Promise(function(resolve, reject) {
    let tempObj = {...obj}
    for (let i = 0; i < props.length; i++) {
      // 如果找到该属性，将该属性存储起来继续寻找下一个属性，直到循环结束
      if (hasProp(tempObj, props[i])) {
        tempObj = tempObj[props[i]]
      } else { // 找不到则返回错误信息
        return reject('找不到' + props[i] + '属性')
      }
    }
    return resolve(tempObj)
  })
}
// 使用
let obj = {
  user: {
    name: 'anguer'
  }
}
get(obj, 'user', 'name').then(function(res) {
  console.log(res) // print 'anguer'
}).catch(function(err) {
  console.log(err)
})

Answer 2

Boleh ke ni?

function get (obj) {
    var scope = { obj: obj }
    var path = 'scope.obj.' + Array.prototype.slice.call(arguments, 1).join('.')
    var value = null
    var NONE = '值为空'
    try {
        value = (new Function('scope', 'return ' + path + ';'))(scope)
        if (value === null || value === undefined) {
            return NONE 
        } else {
            return value
        }
    } catch (e) {
        return NONE 
    }
}

var obj = { k1: { k2: { k3: 1}}}
get(obj, 'k1', 'k2', 'k3') // 1
get(obj, 'k1', 'k', 'k3')  // 值为空

Answer 3

class Tang {
  constructor() {
    this.obj = null;
    this.keys = [];
    this.thenF = [];
    this.elseF = [];
  }
  then(fn) {
    this.thenF.push(fn);
    return this;
  }
  _init() {
    let [obj, ...keys] = arguments;
    this.obj = obj;
    this.keys = keys;
    setTimeout(() => this._start(), 0)
    return this;
  }

  _start() {
    while(this.keys.length && this.obj) {
      this.obj = this.obj[this.keys.shift()];
    }

    if (!this.keys.length) {
      this.thenF.forEach(fn => fn(this.obj));
    } else {
      this.elseF.forEach(fn => fn());
    }
  }
  
  else(fn) {
    this.elseF.push(fn);
    return this;
  }
}
let obj = {k1:{k2:{k3:1}}};
let tang = new Tang();
let get = tang._init.bind(tang);
get(obj,'k1','k2','k3')
    .then((v)=>console.log(v))
    .else(()=>console.log('值为空'));

Bila tengok chain call tu, terfikir lazyman dari dulu.
Pelaksanaannya agak jelek. . .

Answer 4

Sila rujuk

function get (obj, ...keys) {
  try {
    let value = keys.reduce((o, k) => o[k], obj)
    return {
      then (cb) {
        if (typeof cb === 'function') { cb(value) }
        return {else () {}}
      }
    }
  } catch (e) {
    return {
      then () {
        return {
          else (cb) {
            if (typeof cb === 'function') { cb(e) }
          }
        }
      }
    }
  }
}