$_POST[] tidak dapat nilai, kenapa???

Question

gema <<<'FORM'

<form action="" method="post">

<input type="number" name = "rows">行

<br />

<input type="number" name = "cols">列

<input type="submit" value="提交";

</form>

FORM;

$baris = isset($_POST['baris']) ? $_POST['rows'] : 3;

$cols = isset($_POST['cols']) ? $_POST['cols'] : 3;

// $rows = $_POST['rows'];

// $cols = $_POST['cols'];

echo '<table border=" 1" cellspacing="0" cellpadding="5">';

$i = 0;

sambil ($i<$rows) {

echo '<tr>';

$j = 0 ;

manakala ($j<$cols) {

echo '<td>'.($i * $cols + $j).'</td>';

$j++;

}

echo '</tr>';

$i++;

}

echo '</table>';

代码如上,获取不刌取不咰埡的

Answer 1

Tukar nilai tindakan dalam borang kepada nama fail semasa, seperti ini<form action="xx.php" method="post">