如要处理以下markdown:
# I miss you my name is Gina, This is my cloum: [sdf df](http://zhuanlan.zhihu.com/xxxzzz) and this is my weibo:[sina blog](https://link.zhihu.com/?target=http%3A//weibo.com/u/2355944%3Fis_hot%3D1)
我写的代码:
from __future__ import unicode_literals, print_function import re content=''' # I miss you my name is Gina, This is my cloum: [sdf df](http://zhuanlan.zhihu.com/xxxzzz) and this is my weibo:[sina blog](https://link.zhihu.com/?target=http%3A//weibo.com/u/2355944%3Fis_hot%3D1) ''' linklist = re.findall('\[(.+?)\]\((.+?)\)',content,re.S) for link in linklist: link[0].replace("\r\n","") link[1].replace("\r\n","") link[1].replace('https://ref.zhihu.com/?redrict=','') print (content)
显而易见的。。以上代码不能运行。。如何得到我想要的:
# I miss you my name is Gina, This is my cloum: [sdfdf](http://zhuanlan.zhihu.com/xxxzzz) and this is my weibo:[sina blog](http://weibo.com/u/2355944?is_hot=1)
直接replace就可以了~
python3