javascript - 怎么做一个网站的被访问记录数据

Answer 1

function getip(){
    static $ip = '';
    $ip = $_SERVER['REMOTE_ADDR'];
    if (isset( $_SERVER['HTTP_CDN_SRC_IP'] )) {
        $ip = $_SERVER['HTTP_CDN_SRC_IP'];
    } elseif (isset( $_SERVER['HTTP_CLIENT_IP'] ) && preg_match('/^([0-9]{1,3}\.){3}[0-9]{1,3}$/', $_SERVER['HTTP_CLIENT_IP'])) {
        $ip = $_SERVER['HTTP_CLIENT_IP'];
    } elseif (isset( $_SERVER['HTTP_X_FORWARDED_FOR'] ) AND preg_match_all('#\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}#s', $_SERVER['HTTP_X_FORWARDED_FOR'], $matches)) {
        foreach ($matches[0] AS $xip) {
            if (!preg_match('#^(10|172\.16|192\.168)\.#', $xip)) {
                $ip = $xip;
                break;
            }
        }
    }
    return $ip;
}

Answer 2

为什么不用第三方呢，百度统计啊之类的，申请入驻，拿到代码，放到你代码中，通过后台就可以看到了

Answer 3

可以在最前端加入一个过滤器，从requset的头部中获取ip，或者进行一些统计的操作，类似node(express)是

const ip = req.headers['x-forwarded-for'] ||
                req.connection.remoteAddress ||
                req.socket.remoteAddress;
 
// 一些统计的代码
...

// 再往下传递
next();

Answer 4

直接在你数据库加个表呗