javaweb项目已经发布起来了,可是输入controller对应的地址,总是自己跳转到login?
天蓬老师
天蓬老师 2017-04-18 10:55:58
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web.xml中没看出异常啊?

比如输入http://localhost:8080/dyn2/dy...
会自动调整到http://localhost:8080/dyn2/login

<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
 <description>Dynamic Matrix powered by Spring</description>
 <display-name>Dynamic Matrix</display-name>
 <context-param>
  <param-name>webAppRootKey</param-name>
  <param-value>dyn2.root</param-value>
 </context-param>
 <context-param>
  <param-name>log4jConfigLocation</param-name>
  <param-value>/WEB-INF/log4j.properties</param-value>
 </context-param>
 <context-param>
  <param-name>contextConfigLocation</param-name>
  <param-value>/WEB-INF/applicationContext.xml</param-value>
 </context-param>
 <filter>
  <filter-name>characterEncodingFilter</filter-name>
  <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
  <init-param>
   <param-name>encoding</param-name>
   <param-value>utf8</param-value>
  </init-param>
 </filter>
 <!--<filter>
  <filter-name>ContentTypeFilter</filter-name>
  <filter-class>net.counters.dynm.web.ContentTypeFilter</filter-class>
  <init-param>
   <param-name>charset</param-name>
   <param-value>utf8</param-value>
  </init-param>
 </filter>
 -->
 <filter>
  <filter-name>springSecurityFilterChain</filter-name>
  <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
 </filter>
 <!-- <filter>
  <filter-name>UrlRewriteFilter</filter-name>
  <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>
 </filter> -->
 <filter-mapping>
  <filter-name>characterEncodingFilter</filter-name>
  <url-pattern>/*</url-pattern>
 </filter-mapping>
 <!--<filter-mapping>
  <filter-name>ContentTypeFilter</filter-name>
  <url-pattern>/*</url-pattern>
 </filter-mapping>
 -->
 <filter-mapping>
  <filter-name>springSecurityFilterChain</filter-name>
  <url-pattern>/*</url-pattern>
 </filter-mapping>
 <!-- <filter-mapping>
  <filter-name>UrlRewriteFilter</filter-name>
  <url-pattern>/*</url-pattern>
 </filter-mapping> -->
 <listener>
  <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
 </listener>
 <listener>
  <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
 </listener>
 <listener>
     <listener-class>org.springframework.web.util.HttpSessionMutexListener</listener-class>
 </listener>
 <servlet>
  <servlet-name>dynMatrix</servlet-name>
  <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
  <load-on-startup>1</load-on-startup>
 </servlet>
 <!-- <servlet-mapping>
  <servlet-name>dynMatrix</servlet-name>
  <url-pattern>/app/*</url-pattern>
 </servlet-mapping> -->
 <servlet-mapping>
  <servlet-name>dynMatrix</servlet-name>
  <url-pattern>/</url-pattern>
 </servlet-mapping>
 <session-config>
     <session-timeout>60</session-timeout>
 </session-config>
 <error-page>
  <error-code>403</error-code>
  <location>/errors/403.html</location>
 </error-page>
</web-app>

这是controller

    @RequestMapping(value="/create",method=RequestMethod.GET)
    public String getCreateForm(Model model){
        this.addEnableMap(model);
        model.addAttribute(new WebUser());
        //加载分类
        String cwhere = " where type_parent_id=0";
        List<CheckListType> checkListType = checkLMDao.getCheckListTypeByWhere(cwhere, 0, 0);
        
        model.addAttribute("checkListType", checkListType);
        return "createUserForm";
    }
天蓬老师
天蓬老师

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membalas semua(2)
Ty80

Meminta alamat ini mungkin memerlukan beberapa maklumat log masuk untuk pengesahan Permintaan dalam ajax akan menghantar maklumat ini
Jika anda memasukkannya secara langsung ke dalam penyemak imbas tanpa maklumat ini, ia akan dipintas dan dimajukan oleh penapis keselamatan halaman log masuk.

刘奇


Mungkin penapis ini memintas permintaan anda
Adakah anda bertanggungjawab untuk projek itu sahaja? Jika ini bukan soalan seperti ini, sebaiknya tanya rakan sekerja dalam pasukan projek yang sama

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