JTextField t1 = new JTextField(" ");
String a = t1.getText();
int intA = Integer.parseInt(a);
System.out.println(intA);
Error
java.lang.NumberFormatException: For input string: "1 "
附上我的代码
public class Testing extends JPanel {
public int s;
public Testing() {
JPanel p = new JPanel();
JTextField t1 = new JTextField(" ");
JTextField t2 = new JTextField(" ");
JTextField t3 = new JTextField(" ");
JButton b3 = new JButton("result");
p.add(t1);
p.add(t2);
p.add(t3);
p.add(b3);
add(p);
b3.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
try {
String a = t1.getText();
int intA = Integer.parseInt(a);
System.out.println(intA);
// String b = t2.getText();
//t3.setText(a+"");
} catch (NumberFormatException ignored) {
System.out.println(ignored);
}
}
});
}
public static void main(String... arg) {
Testing p = new Testing();
JFrame frame = new JFrame();
frame.add(p);
frame.setLocationRelativeTo(null);
frame.pack();
frame.setVisible(true);
}
}
//Panduan pakej.
import javax.swing.*;
import java.awt.event.*;
kelas JTextFieldDemo
{
}
Ringkasnya:
Masalah di atas berlaku kerana kaedah jtf.getText(); dilaporkan. (Pendapat saya yang rendah hati, hehe)
Terima kasih @Sjs_k atas jawapannya
Tukar sahaja
JTextField t1 = new JTextField("");
kepadaJTextField t1 = new JTextField(5);
dan ia akan baik-baik saja