关于laravel中路由跳转控制器的问题

WBOY
Release: 2016-06-06 20:19:02
Original
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我现在有这样类型的链接:
http://www.xxx.com/api/signup

其中api是控制器ApiController

需要变换的是signup,有可能是signin,create,del,move等

请问在路由里面怎么写,才能让后面的值对应到指定的控制器中的方法

也就是访问http://www.xxx.com/api/signup对应到api控制器下的signup方法,同理signin,create,del,move

回复内容:

我现在有这样类型的链接:
http://www.xxx.com/api/signup

其中api是控制器ApiController

需要变换的是signup,有可能是signin,create,del,move等

请问在路由里面怎么写,才能让后面的值对应到指定的控制器中的方法

也就是访问http://www.xxx.com/api/signup对应到api控制器下的signup方法,同理signin,create,del,move

Route::controller('api', 'ApiController', [

<code>'signup' => 'api.signup',
'signin' => 'api.signin',
'create' => 'api.create',
'del' => 'api.del',
'move' => 'api.move',</code>
Copy after login

]);

class ApiController extends Controller
{

<code>
public function getSignup()
{
    return 'index';
}

public function getSignin()
{
    return 'create';
}
..........</code>
Copy after login

}

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