Home > Backend Development > PHP Tutorial > 如何改这段thinkphp签到代码

如何改这段thinkphp签到代码

WBOY
Release: 2016-06-06 20:22:07
Original
1629 people have browsed it

<code>        $residueHour=24+24-date('H',$lastSignDay);
        $formatHour=strtotime(date('Y-m-d H',$lastSignDay).':00:00');
        $lastSignDate=strtotime("+{$residueHour}hour",$formatHour);</code>
Copy after login
Copy after login

回复内容:

<code>        $residueHour=24+24-date('H',$lastSignDay);
        $formatHour=strtotime(date('Y-m-d H',$lastSignDay).':00:00');
        $lastSignDate=strtotime("+{$residueHour}hour",$formatHour);</code>
Copy after login
Copy after login

<code>public function sign(){
    //每日签到       
    $this->check_login();
    $data=array(
            'userId'=>$this->memberID,
            'sc_score'=>1,
            'sc_detail'=>'签到+1',
            'sc_type'=>1
    );
    
    $dao=M('sign');//实例化sign对象
    $current=date('Y-m-d H:i:s',time());
    $hasSign=$dao->where("userId={$this->memberID}")->find();
    $count=$hasSign['si_count'];
    if($hasSign){
        $lastSignDay=strtotime("{$hasSign['si_time']}");
        $lastSign=date('Y-m-d',$lastSignDay);
        $today=date('Y-m-d',time());
         if($lastSign==$today){
            echo "今天已签到,您已连续签到 <font color="green"> {$count} </font> 天,连续签到5天每天+5元代金券!";
            exit();
        } 
            
        $residueHour=24+24-date('H',$lastSignDay); //有效的签到时间  (签到当天剩余的小时+1天的时间)
        $formatHour=strtotime(date('Y-m-d H',$lastSignDay).':00:00');//签到当天 2014-12-07 18:00:00
        $lastSignDate=strtotime("+{$residueHour}hour",$formatHour);//在2014-12-07 18:00:00 基础上+ 有效的签到时间
        if(time()>$lastSignDate){ //当前时间 >  上一次签到时间
            $count=1;  
        }else{
            $count=$count+1;
        }
        $sign=$dao->where("userId={$this->memberID}")->save(array('si_time'=>$current,'si_count'=>$count)); //签到表
    }else{
        $sign=$dao->add(array('userId'=>$this->memberID,'si_count'=>1)); //签到表
        $count=1;
    }
    if($sign){
        //第一天签到+1 第二天签到+2 第三天签到+3 第四天签到+4 第五天+5 连续5天每天+5
        switch ($count){
            case 1:
              $sc_score=1;
              break;
            case 2:
              $sc_score=2;
              break;
            case 3:
              $sc_score=3;
              break;
            case 4:
              $sc_score=4;
              break;
            default:
              $sc_score=5;
            }
            $dao->where("userId={$this->memberID}")->setInc('coin',$sc_score);  //签到金额累加
            $coin=$dao->where("userId={$this->memberID}")->field('coin')->find();
            if($coin['coin']>=20){
                $dao->where("userId={$this->memberID}")->setDec('coin',20);//如果满20将生成一张20的代金券
                $this->insertCoupon('会员签到代金券',20,$this->memberID);
            }
            $data=array(
            'userId'=>$this->memberID,    
            'sc_score'=>$sc_score,    
            'sc_detail'=>'签到+'.$sc_score,    
            'sc_type'=>1    
            );
        
        M('score2')->add($data); //积分表
                    
        if($count>0){
            echo "<font color="green">您今天已成功签到,成功领取{$sc_score}元代金券,其中连续签到 <font color="red"> {$count} </font> 天</font>";
        }else{
            echo "<font color="green">签到成功</font>";
        }
    
    }else{
        echo '签到失败,请稍后重试!';
    }
    
}</code>
Copy after login
Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template