求该结果的preg_replace的轮换写法

$url = 'http://www.xxx.com/66/';<br />
@preg_replace("#/(\d{2,4})/?$#e","\$t=array('name'=>'index.php','param'=>array('t'=>1,'id'=>$1))",strtolower($url));<br />
print_r($t);<br />

$url='http://www.xxx.com/66/';<br />
$s= preg_replace("#\/(\d{2,4})\/?$#","/name/index.php?t=1&id=$1",strtolower($url));<br />
$ar=parse_url($s);<br />
$arr['name']=substr($ar['path'],strrpos($ar['path'],'/')+1);<br />
parse_str($ar['query'],$t);<br />
$arr['param']=$t;<br />
print_r($arr);