Ajax asynchronous request for PHP data_PHP tutorial-PHP Tutorial-php.cn

Ajax asynchronous request for PHP data_PHP tutorial

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Release： 2016-07-13 10:14:59

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Ajax asynchronous request for PHP data

I received an assignment from the teacher, and the implemented layout is as shown below:

If the department ID is entered, only the department name corresponding to the ID will be displayed. If not, all will be displayed. Then based on the value of the I department name, the text box in the corresponding major department will automatically display the major department where the department name is located. . For example: if Cardiovascular Medicine is selected, Internal Medicine will be displayed in the corresponding major department.

The main code is as follows:

Request department based on ID

function showHint(str)
{
    var xmlhttp;
    if (window.XMLHttpRequest)
     {// IE7+, Firefox, Chrome, Opera, Safari
        xmlhttp=new XMLHttpRequest();
     }
      else
     {// IE6, IE5
        xmlhttp=new ActiveXObject(Microsoft.XMLHTTP);
     }
     xmlhttp.onreadystatechange=function()
    {
       if (xmlhttp.readyState==4 && xmlhttp.status==200)
      {
        document.getElementById(txtHint).innerHTML=xmlhttp.responseText;
      }
  }
    xmlhttp.open(GET,keshi.php?q=+str,true);
    xmlhttp.send();
}

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keshi.php:

<!--?php
/*防止恶意调用*/
define(TEST,'test');
// 引入文件
include_once 'mysql.func.php';
// 数据库初始化
connectMySQL();
selectDB();
setZiFuJi();

//获得来自 URL 的 q 参数
$q=$_GET[q];
//如果 q 是数字或者数字字符串
if (is_numeric($q))
  {
    $q = intval($q);
    $hint=;
    $resultDKQ = queryDB(select name from table_dake where id=$q);
    $hint = '科室名字：<select name=ksname id=ksname onchange=show(this.options[this.selectedIndex].value)-->&#39;;
    while (!!$rowDKQ = fetchAssoc($resultDKQ))
    {
      $hint .= &#39;

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'; $resultKSQ = queryDB(select table_dake.id,table_keshi.sid,table_keshi.name from table_dake,table_keshi where table_dake.name='{$rowDKQ['name']}' and table_keshi.sid=table_dake.id ); while(!!$rowKSQ = fetchAssoc($resultKSQ)) { $hint .= ''; } $hint .= '' ; } } // Not a number else { $resultDK = queryDB(select table_dake.name from table_dake); $hint = 'Department name: