Introduction to the method of determining the image format of file upload in PHP-PHP Tutorial-php.cn

Introduction to the method of determining the image format of file upload in PHP

黄舟

Release： 2023-03-16 14:36:01

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This article mainly introduces relevant information about the detailed explanation of the example of PHP judging the file upload image format. I hope this article can help everyone implement this method. It is very valuable for reference. Friends in need can refer to it

php Detailed example of determining the file upload image format

Determine the file image type,

 $type  = $_FILES[&#39;image&#39;][&#39;tmp_name&#39;];//文件名
 //$type  = $this->getImagetype( $type ); 
 $filetype = [&#39;jpg&#39;, &#39;jpeg&#39;, &#39;gif&#39;, &#39;bmp&#39;, &#39;png&#39;];
 if (! in_array($type, $filetype))
 { 
  return "不是图片类型";
 ｝

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As above, if the user modifies the file suffix to png jpeg If you can't satisfy it, I checked the information and the solution is to use the binary stream information of the file to judge. If you happen to encounter this kind of problem, you might as well try it:

 //*判断图片上传格式是否为图片 return返回文件后缀
 public function getImagetype($filename)
 {
  $file = fopen($filename, &#39;rb&#39;);
  $bin = fread($file, 2); //只读2字节
  fclose($file);
  $strInfo = @unpack(&#39;C2chars&#39;, $bin);
  $typeCode = intval($strInfo[&#39;chars1&#39;].$strInfo[&#39;chars2&#39;]);
  // dd($typeCode);
  $fileType = &#39;&#39;;
  switch ($typeCode) {
   case 255216:
    $fileType = &#39;jpg&#39;;
    break;
   case 7173:
    $fileType = &#39;gif&#39;;
    break;
   case 6677:
    $fileType = &#39;bmp&#39;;
    break;
   case 13780:
    $fileType = &#39;png&#39;;
    break;
   default:
    $fileType = &#39;只能上传图片类型格式&#39;;
  }
  // if ($strInfo[&#39;chars1&#39;]==&#39;-1&#39; AND $strInfo[&#39;chars2&#39;]==&#39;-40&#39; ) return &#39;jpg&#39;;
  // if ($strInfo[&#39;chars1&#39;]==&#39;-119&#39; AND $strInfo[&#39;chars2&#39;]==&#39;80&#39; ) return &#39;png&#39;;
  return $fileType;
 }

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