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How to output json object in php

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Release： 2023-03-22 08:50:02
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This time I will show you how to output json objects in PHP. What are the precautions for outputting JSON objects in PHP? The following is a practical case, let's take a look.

An example is as follows: 

 <!DOCTYPE html>
<html>
<body>
<?php
 
$json = &#39;{"report":{"date":"2012-04-10","content":"abcdefght"}}&#39;;
 $arr = (array) json_decode($json,true);
 echo &#39;当前日期是：&#39;. $arr[&#39;report&#39;][&#39;date&#39;];
echo "<br/>";
echo '<pre class="brush:php;toolbar:false">';
 print_r($arr);
echo '
';     foreach($arr as $arrvalue)  {  foreach($arrvalue as $key=>$value)  {   echo "[$key] = $value 
";  }  } echo "
"; ?>  
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<!DOCTYPE html>
<html>
<body>
<?php
$file_exists = file_exists("json.txt");
if( $file_exists ){
 $myfile = fopen("json.txt", "r") or die("");
 $content = fread($myfile,filesize("json.txt"));
 fclose($myfile);
 echo $content;
 echo "<br/>";
 $arr=(array)json_decode($content,true);
 echo $arr['CSS'];
 echo "<br/>";
 echo $arr['AJAX'];
}
?>
 
</body>
</html>
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json.txt:

{
 "AJAX": "Asynchronous JavaScript and XML",
 "CSS": "Cascading Style Sheets"
}
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I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!

Recommended reading:

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Related labels：
javascript json php
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