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How to output json object in php

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Release： 2023-03-22 08:50:02
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This time I will show you how to output json objects in PHP. What are the precautions for outputting JSON objects in PHP? The following is a practical case, let's take a look.

An example is as follows: 

 <!DOCTYPE html>
<html>
<body>
<?php
 
$json = &#39;{"report":{"date":"2012-04-10","content":"abcdefght"}}&#39;;
 $arr = (array) json_decode($json,true);
 echo &#39;当前日期是：&#39;. $arr[&#39;report&#39;][&#39;date&#39;];
echo "<br/>";
echo '<pre class="brush:php;toolbar:false">';
 print_r($arr);
echo '
';     foreach($arr as $arrvalue)  {  foreach($arrvalue as $key=>$value)  {   echo "[$key] = $value 
";  }  } echo "
"; ?>  
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<!DOCTYPE html>
<html>
<body>
<?php
$file_exists = file_exists("json.txt");
if( $file_exists ){
 $myfile = fopen("json.txt", "r") or die("");
 $content = fread($myfile,filesize("json.txt"));
 fclose($myfile);
 echo $content;
 echo "<br/>";
 $arr=(array)json_decode($content,true);
 echo $arr['CSS'];
 echo "<br/>";
 echo $arr['AJAX'];
}
?>
 
</body>
</html>
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json.txt:

{
 "AJAX": "Asynchronous JavaScript and XML",
 "CSS": "Cascading Style Sheets"
}
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I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!

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Related labels：
javascript json php
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