Detailed graphic and text explanation of how php obtains the number of days of the month and date array based on the year and month-PHP Tutorial-php.cn

Detailed graphic and text explanation of how php obtains the number of days of the month and date array based on the year and month

墨辰丷

Release： 2023-03-28 12:54:02

Original

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This article mainly introduces the method of PHP to obtain the number of days of the current month and date array according to the year and month, involving PHP's related judgment and conversion of dates and the traversal operations of characters and arrays. Friends who need it can refer to it

The details are as follows:

function get_day( $date )  
{
    $tem = explode(&#39;-&#39; , $date); //切割日期 得到年份和月份
    $year = $tem[&#39;0&#39;];
    $month = $tem[&#39;1&#39;];
    if( in_array($month , array( 1 , 3 , 5 , 7 , 8 , 01 , 03 , 05 , 07 , 08 , 10 , 12)))
    {
      // $text = $year.&#39;年的&#39;.$month.&#39;月有31天&#39;;
      $text = &#39;31&#39;;
    }
    elseif( $month == 2 )
    {
      if ( $year%400 == 0 || ($year%4 == 0 && $year%100 !== 0) )    //判断是否是闰年
      {
        // $text = $year.&#39;年的&#39;.$month.&#39;月有29天&#39;;
        $text = &#39;29&#39;;
      }
      else{
        // $text = $year.&#39;年的&#39;.$month.&#39;月有28天&#39;;
        $text = &#39;28&#39;;
      }
    }
    else{
      // $text = $year.&#39;年的&#39;.$month.&#39;月有30天&#39;;
      $text = &#39;30&#39;;
    }
    return $text;
}
echo get_day(&#39;2016-8-1&#39;);

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The operation result is: 31

Transformation, return date array:

/**
* 获取当月天数
* @param $date 
* @param $rtype 1天数 2具体日期数组
* @return 
*/
function get_day( $date ,$rtype = &#39;1&#39;)  
{
    $tem = explode(&#39;-&#39; , $date);    //切割日期 得到年份和月份
    $year = $tem[&#39;0&#39;];
    $month = $tem[&#39;1&#39;];
    if( in_array($month , array( 1 , 3 , 5 , 7 , 8 , 01 , 03 , 05 , 07 , 08 , 10 , 12)))
    {
      // $text = $year.&#39;年的&#39;.$month.&#39;月有31天&#39;;
      $text = &#39;31&#39;;
    }
    elseif( $month == 2 )
    {
      if ( $year%400 == 0 || ($year%4 == 0 && $year%100 !== 0) )    //判断是否是闰年
      {
        // $text = $year.&#39;年的&#39;.$month.&#39;月有29天&#39;;
        $text = &#39;29&#39;;
      }
      else{
        // $text = $year.&#39;年的&#39;.$month.&#39;月有28天&#39;;
        $text = &#39;28&#39;;
      }
    }
    else{
      // $text = $year.&#39;年的&#39;.$month.&#39;月有30天&#39;;
      $text = &#39;30&#39;;
    }
    if ($rtype == &#39;2&#39;) {
      for ($i = 1; $i <= $text ; $i ++ ) {
        $r[] = $year."-".$month."-".$i;
      }
    } else {
      $r = $text;
    }
    return $r;
}
var_dump(get_day(&#39;2016-8-1&#39;,&#39;2&#39;));

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The running results are as follows:

array(31) {
 [0]=>
 string(8) "2016-8-1"
 [1]=>
 string(8) "2016-8-2"
 [2]=>
 string(8) "2016-8-3"
 [3]=>
 string(8) "2016-8-4"
 [4]=>
 string(8) "2016-8-5"
 [5]=>
 string(8) "2016-8-6"
 [6]=>
 string(8) "2016-8-7"
 [7]=>
 string(8) "2016-8-8"
 [8]=>
 string(8) "2016-8-9"
 [9]=>
 string(9) "2016-8-10"
 [10]=>
 string(9) "2016-8-11"
 [11]=>
 string(9) "2016-8-12"
 [12]=>
 string(9) "2016-8-13"
 [13]=>
 string(9) "2016-8-14"
 [14]=>
 string(9) "2016-8-15"
 [15]=>
 string(9) "2016-8-16"
 [16]=>
 string(9) "2016-8-17"
 [17]=>
 string(9) "2016-8-18"
 [18]=>
 string(9) "2016-8-19"
 [19]=>
 string(9) "2016-8-20"
 [20]=>
 string(9) "2016-8-21"
 [21]=>
 string(9) "2016-8-22"
 [22]=>
 string(9) "2016-8-23"
 [23]=>
 string(9) "2016-8-24"
 [24]=>
 string(9) "2016-8-25"
 [25]=>
 string(9) "2016-8-26"
 [26]=>
 string(9) "2016-8-27"
 [27]=>
 string(9) "2016-8-28"
 [28]=>
 string(9) "2016-8-29"
 [29]=>
 string(9) "2016-8-30"
 [30]=>
 string(9) "2016-8-31"
}

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The above is the entire content of this article, I hope it will be helpful to everyone learning helps.

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