How to mosaic part of a picture through php

jacklove
Release: 2023-03-31 08:12:02
Original
1844 people have browsed it

php Partial mosaic of pictures

Principle:

Yes For each pixel of the selected area in the image, increase the width and height to create a rectangle. The rectangles of each pixel overlap to form a mosaic effect.

This example uses imagecolorat of the GD library to obtain the pixel color, and imagefilledrectangle to draw a rectangle.

Rendering:

##The code is as follows:

<?php
/** 图片局部打马赛克
* @param  String  $source 原图
* @param  Stirng  $dest   生成的图片
* @param  int     $x1     起点横坐标
* @param  int     $y1     起点纵坐标
* @param  int     $x2     终点横坐标
* @param  int     $y2     终点纵坐标
* @param  int     $deep   深度,数字越大越模糊
* @return boolean
*/
function imageMosaics($source, $dest, $x1, $y1, $x2, $y2, $deep){

    // 判断原图是否存在
    if(!file_exists($source)){
        return false;
    }

    // 获取原图信息
    list($owidth, $oheight, $otype) = getimagesize($source);

    // 判断区域是否超出图片
    if($x1>$owidth || $x1<0 || $x2>$owidth || $x2<0 || $y1>$oheight || $y1<0 || $y2>$oheight || $y2<0){
        return false;
    }

    switch($otype){
        case 1: $source_img = imagecreatefromgif($source); break;
        case 2: $source_img = imagecreatefromjpeg($source); break;
        case 3: $source_img = imagecreatefrompng($source); break;
        default:
            return false;
    }

    // 打马赛克
    for($x=$x1; $x<$x2; $x=$x+$deep){
        for($y=$y1; $y<$y2; $y=$y+$deep){
            $color = imagecolorat($source_img, $x+round($deep/2), $y+round($deep/2));
            imagefilledrectangle($source_img, $x, $y, $x+$deep, $y+$deep, $color);
        }
    }

    // 生成图片
    switch($otype){
        case 1: imagegif($source_img, $dest); break;
        case 2: imagejpeg($source_img, $dest); break;
        case 3: imagepng($source_img, $dest); break;
    }

    return is_file($dest)? true : false;

}

$source = &#39;source.jpg&#39;;
$dest = &#39;dest.jpg&#39;;

$flag = imageMosaics($source, $dest, 176, 98, 273, 197, 4);
echo &#39;<img src="&#39;.$source.&#39;">&#39;;
echo &#39;<img src="&#39;.$dest.&#39;">&#39;;

?>
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