Regular expression - how to match square bracket pairs in vim

Question

It seems that I use \[ to match [, use ] to match]. I use \[*] to match the square bracket pair, but a\[*] cannot match the bracket pair with a in front (array a) , but using a\[ can match a and the left bracket after a. Why?

Answer 1

\[*]匹配的是0到多个[，后面是一个]，例如],[],[[]等
中间的*匹配的[，并不是指中括号中间的任意字符重复0-N次。

中括号中间的任意字符，简单的话可以使用.*表示，但是同一行有多个中括号的话会全部匹配，如：
a[i+1]= b[i-1]这样的表达式会被全部匹配。

试一下下面这个，应该可以匹配a后面的带中括号的表达式
a\[[^]]*]   

Answer 2

My test result is a[*] 可以匹配到 a[]。当然它不能匹配 a[i].

But are you sure you want to use *? Your "like" makes me have the urge to give you a tutorial on regular expressions...

[...] 是用来匹配字符类的，比如 [abd] 匹配 a, b 或者 d 中的任何一个。因为 [] 已经有这个意思了，所以要匹配到 [ 字符需要转义 [，要匹配 ] 的话原则上也是要转义的 ], but it does not need to be escaped when it does not cause ambiguity.

* 是一个量词，它表示前边那个字符（或者字符类、字符组 is a quantifier, which means that the previous character (or character class, character group) can appear anywhere Multiple times (0 times also counts).