Java uses the simplest if to determine whether the date is early or late
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给我你的怀抱 2017-05-17 10:08:33
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The date consists of three int data, namely year, month, day. You cannot use any function, just use the simplest if to judge. Does anyone have any simple method?

Routine: if is nested inside if, if year is equal, determine month, and then determine day
Direct year1000000 month100 day One if can be done

给我你的怀抱
给我你的怀抱

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曾经蜡笔没有小新

Just convert year month day into string, then add them and compare them, just like sorting. Note that month and day must be two digits, and 0 is added for one digit

PHPzhong

If you consider the simplicity of the code, then your method is indeed good, but from a performance perspective, three ifs are much more efficient than multiplication

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