javascript - How to slide the screen on the mobile phone to get the distance from the top of a certain element? At the same time, can this value be referenced by other functions?

Question

As the title says, what I want to achieve is to slide the mobile phone screen. When an element is a certain value from the top (for example, 200px), click the pop-up button on the screen, and the position of the pop-up layer will be 200px from the top

$(document).ready(function(){
    $('.content_box').bind('touchstart', function(e) {
        var a =$(".article_box").offset().top;
        distance = a;
        console.log(distance);
    });
});
//执行函数
function show_taboo(){
    if(distance>200){
        alert("出现了")//做处理
    }else{
        alert("隐藏")、、处理
}

What I want to achieve is this effect. The value of distance can be obtained, but it cannot be referenced in the show function. Can you please help me?

Answer 1

The solution found is as follows:
$(document).ready(function(){

         $('.content_box').bind('touchstart', test());
 });

//Define function
function test(){

 return $(".content_box").offset().top;      

}
//Execute function
function show_taboo(){

distance = test();//获得监听事件的值
if(distance>200){
    alert("出现了")//做处理
}else{
    alert("隐藏") //处理
}

}

Answer 2

$(document).ready(function(){
                    $('.content_box').bind('touchstart', function(e) {
                    var a = $(".content_box").offset().top;
                    distance = a;
                    console.log(distance)
                    return show_taboo(distance)
                    });
            });
            //执行函数
            function show_taboo(distance){
                if(distance>200){
                    alert("出现了")//做处理
                }else{
                    alert("隐藏") //处理
                }
            }