javascript - problem of preserving decimals in integers

Question

I hope to keep a number to two decimal places. If there are decimal places, round them off. If not, fill in 0.
For example,
1=》1.00
1.234=》1.23
1.256=》1.26

I tried using the toFixed function, and its content is correct, but it returns a string. For example, 1.00 is a string. When I explicitly convert Number(1.00), it becomes 1.

So how do I get the number to retain two decimal places and the return type is a number?

Answer 1

My guess is: If it is used for page display, then strings don’t matter, right? If it is used for operation, it doesn't matter even if it is 1 (not 1.00), right?

Answer 2

1.00 This format can only be saved as a string, and cannot be saved as a numeric type.

No matter what you do, if you want to display something like 1.00, you can only use strings.

Answer 3

First of all, the toFixed method itself is buggy. Secondly, the Number structure in js does not contain precision. If you need numbers that contain precision, you can just write a class yourself

Answer 4

var num=1.256;
Math.floor(Math.round(num*100))/100;

可以封装成方法：
function unitNormalization(arr,digit){
        /*单位规整*/
        var digit=digit||0;
        var prence=Math.pow(10,digit);
        if(Array.isArray(arr)){
            var backArr=[];
            for(var i=0;i<arr.length;i++){
                backArr.push(Math.rou(Math.round(arr[i]*prence))/prence);
            }
            return backArr;
        }else{
            var num=Math.floor(Math.round(arr*prence))/prence;
            return num
        }
    }

unitNormalization(1.253,2)//1.25
unitNormalization(1.257,2)//1.26

Answer 5

parseFloat(1.236.toFixed(2))