JavaScript about operator precedence

Question

Foo.bar = () => { ... }

function Foo() { ... }

Foo.prototype.bar = () => { ... }

new Foo.bar(); (1)

new Foo().bar(); (2)

(1) can be understood as new (Foo.bar)()

(2)The actual execution is (new Foo()).bar() =>This does not comply with the operator precedence rules. Unary operator<Attribute extraction and calling function operator (. [] ())

Answer 1

new new Foo() 跟成员访问 .barwith parameter list has the same priority, from left to right.

new without parameter list new Foo One level lower.