Equivalent writing of code.co_kwonlyargcount in Python2

Question

Suppose there is such a piece of code:

>>> def add (x,y):
...     return x + y
... 
>>> c = add.__code__

For Python3, we can get the keyword parameter to be 0 through c.co_kwonlyargcount. For Python2, how to implement equivalent writing and get the corresponding keyword parameter? quantity.

Answer 1

https://docs.python.org/2/lib...

Answer 2

The number of parameters obtained by python2 and python3 is different:

def add(x, y):
    return x + y
    
python2:
c = add.func_code
c.co_argcount

python3:
c = add.__code__
c.co_argcount