python scrapy has no other code error prompts. . . only this
TypeError has already given a hint. If I guessed correctly, it should be that the url parameter you passed to yield request() is not a string; the url obtained using xpath is a list, remember to follow it with url[0]
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TypeError has already given a hint. If I guessed correctly, it should be that the url parameter you passed to yield request() is not a string; the url obtained using xpath is a list, remember to follow it with url[0]