javascript - Ask a question about using regular expressions to obtain URL parameters

Question

var url = "https://api.xxx.com/search?name=xxx&age=xxx&sex=xxx";

Given this url, match the parameter string following ? (not including?) through a regular expression. Please tell me how to write the regular expression. Xiaobai asks for advice~~

Answer 1

Because js does not support forward lookahead syntax, it cannot use the syntax (?<=?), so we can only save the country through curves:

var url = "https://api.xxx.com/search?name=xxx&age=xxx&sex=xxx";
var reg = /\?[^"/]+/
var result = reg.exec(url)
para = result[0].slice(1)
console.log(para)

// 输出:
name=xxx&age=xxx&sex=xxx

Answer 2

This does not require regularization.

pos = str.indexOf('?')

str.substring(pos+1)