How does python convert the timestamp to the format of "June 12, 2017 18:24"?
欧阳克
欧阳克 2017-06-13 09:24:50
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How does python convert the timestamp to the format of "June 12, 2017 18:24"? Thanks

import time
timestamp = time.time()
time.strftime('%Y年%m月%d日 %H时%M分', time.localtime(timestamp))
Traceback (most recent call last):
  File "<input>", line 1, in <module>
UnicodeEncodeError: 'locale' codec can't encode character '\u5e74' in position 2: Illegal byte sequence

Another complaint, when opening segmentfault in chrome will show the error of running out of memory and crashing, when will it be fixed?

欧阳克
欧阳克

温故而知新,可以为师矣。 博客:www.ouyangke.com

reply all(2)
漂亮男人
# coding: utf8
import time
timestamp = time.time() - 3600   # 时间戳
print(time.strftime('%Y{y}%m{m}%d{d} %H{H}%M{M}', time.localtime(timestamp)).format(y='年', m='月', d='日', H='时', M='分'))

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I have really researched a universal method. According to my Baidu Google, it seems that this is the only one in the world?

Without further ado, here are the solution principles and solutions:

Official documentation: https://docs.python.org/3/lib...


class time.`struct_time`¶

The type of the time value sequence returned by gmtime(), localtime(), and strptime(). It is an object with a named tuple interface: values ​​can be accessed by index and by attribute name. The following values ​​are present:

Index Attribute Values
0 tm_year (for example, 1993)
1 tm_mon range [1, 12]
2 tm_mday range [1, 31]
3 tm_hour range [0, 23]
4 tm_min range [0, 59]
5 tm_sec range [0, 61]; see (2) in strftime() description
6 tm_wday range [0, 6], Monday is 0
7 tm_yday range [1, 366]
8 tm_isdst 0, 1 or -1; see below
N/A tm_zone abbreviation of timezone name
N/A tm_gmtoff offset east of UTC in seconds

Note that unlike the C structure, the month value is a range of [1, 12], not [0, 11].
In calls to mktime(), tm_isdst may be set to 1 when daylight savings time is in effect, and 0 when it is not. A value of -1 indicates that this is not known, and will usually result in the correct state being filled in.
When a tuple with an incorrect length is passed to a function expecting a struct_time, or having elements of the wrong type, a TypeError is raised.


Looking at the documentation, you can see the tuple structure returned by time.localtime(). What I want to use is the year, month, day, hour, and the first 5, so here’s the code:

import time
print('%s年%s月%s日 %s时%s分' % time.localtime(1497254119.69407)[:5])

Output:

2017年6月12日 15时55分

Done.

Please indicate the source when reprinting, thank you.

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