javascript - Regular expression question and answer
三叔
三叔 2017-06-26 10:50:05
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var html = "<p><a href='http://www.cnblogs.com/rubylouvre/'>Ruby Louvre</a>by <em>司徒正美</em></p>";
var text = html.replace(/<(?:.|\s)*?>/g, "");
console.log(text);//VM247:3 Ruby Louvreby 司徒正美

Please explain this regular expression to me. I really can’t understand π-π. . .
Thank you

三叔
三叔

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女神的闺蜜爱上我
/    # 开始符
<    # 就是<这个字符
(    # 括号表示捕获, 意思是能在 正则的group函数中, 获取相应的值
?:    # 这个又取消括号的捕获功能, 就是上一行的说明无效了.
.    # 单个字符
|    # 逻辑或的意思, 范围为括号中
\s    # 空白
)    # 一对括号
*    # 一个或多个, 这儿表示 一个或多个 括号中的内容
?    # 非贪婪, 表示 前面()* 这个组能少就少
>    # 字符>
/g    # 表示全局搜索, 就是 match_all 的意思.

What you have here is the replacement function, which replaces <xxxx> with empty spaces

世界只因有你

You can go to https://regex101.com/ and try it yourself. You can enter expressions on the left side. Enter the matched content of the test below. There is a detailed explanation on the right.
In addition, the |s in this regular expression is wasteful. You only need to write /<(?:.)*?>/g. If there is no need to operate on the capturing group, there is no need for non-capturing group. necessary. It can be simplified to /<.*?>/g

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