Java basics, please answer.

Question

public class Demo {

             public static void main(String args[]) { 
                 boolean flag = 10%2 == 1 && 10 / 3 == 0 && 1 / 0 == 0 ; 
                 System.out.println(flag ? "mldn" : "yootk") ; 
             } 
         } 
         
         代码如上，我任务考察的是 && 符号 与 & 符号的区别，但是在最后一个  1 / 0 == 0 这个竟然能走通，而且打印出来了yootk，这个除数不是不能为零的吗？为什么能走通呢？很是费解，希望大神可以给解释下，谢谢。

Answer 1

&& and || have a short-circuit effect:
The root cause of the short-circuit effect is to improve performance

&& operator checks whether the first expression returns false. If it is false, the result must be false and no other content is checked.
|| operator checks whether the first expression returns true. If it is true, the result Must be true, no other content will be checked

 public static void main(String args[]) { 
     boolean flag = 10%2 == 1 && 10 / 3 == 0 && 1 / 0 == 0 ; 
     System.out.println(flag ? "mldn" : "yootk") ; 
 } 

10%2 == 1 is false, the following content will no longer be executed

Answer 2

10%2 == 1 is false, the final result of the entire expression is false, and the following will not be executed, which is a short circuit.

Answer 3

&& and || will short-circuit, but & and | will not. If you change && to &, something will definitely happen.