Does the callback function use the closure feature? for example:
$('button').onclick = function(){ /* do sth */};
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A=(x)=>{alert(x)};B=(callback)=>{let y=1;callback(y)};B(A);This way the callback is Used it
No, there is no closure here.
Closure returns function B in function A, and function B always references the layout variable of function A.
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A=(x)=>{alert(x)};
B=(callback)=>{
let y=1;
callback(y)
};
B(A);
This way the callback is Used it
No, there is no closure here.
Closure returns function B in function A, and function B always references the layout variable of function A.