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javascript - Problem with parameters passed in settimeout
三叔
三叔 2017-07-05 11:06:49
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Use settimeout to write the expansion and contraction of the secondary menu. Pass a function with parameters in settimeout. I don’t know how to pass it. In the video, it is written like this: setTimeout("addHeight('" ul "')",10 ) but it’s not normal. What’s the reason?

三叔
三叔

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某草草
某草草2017-07-05 11:08:49 2 floor 
setTimeout(function () {addHeight(ul)},10);
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漂亮男人
漂亮男人2017-07-05 11:08:49 1 floor

setTimeout The first parameter of this function can accept a function or a piece of code. If it is code, put it into eval for execution.

The way you write here is the way you write a piece of code. Please check whether the quotation marks are written correctly in one-to-one correspondence. Or change to the following two writing methods and it should work normally

setTimeout(function () {
    addHeight(ul)
}, 10);
setTimeout(addHeight, 10, ul)
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