There is no problem with the call. It can be called normally. As for whether it is not running because your previous code has stopped, you can send the complete code so that we can use it as a reference.
replyThank you for your answer. I found the problem. It turns out that there is a problem with the for loop in the js function. It needs to be looped 3 times, for (var i=0;i<x;i++). I wrote it 4 times, for (var i=0 ;i<=x;i++), the system will not report an error for this problem, and you need to test it sentence by sentence to find it.
There is no problem with the call. It can be called normally. As for whether it is not running because your previous code has stopped, you can send the complete code so that we can use it as a reference.