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In the process of web development, it is very common to use Ajax for asynchronous data interaction. Among them, jQuery is a very famous JavaScript library. It has a large number of built-in functions and methods to facilitate our front-end development. In jQuery, it is also very simple to use Ajax for asynchronous data interaction. You only need to use the $.ajax() function to achieve it. However, when using the $.ajax() function, we sometimes encounter a problem, that is, the prompt "Ajax is not a method" is displayed. So, what causes this problem?
First of all, we have to make it clear that the "Ajax is not a method" prompt is not caused by jQuery itself. In jQuery, the $.ajax() function is a method defined on the jQuery object. That is to say, when calling the $.ajax() function, we must first instantiate a jQuery object. If we directly use the "Ajax()" function to call Ajax, it will prompt "Ajax is not a method".
So, how to solve it? In fact, solving this problem is very simple. You only need to correctly introduce the jQuery library and instantiate a jQuery object. Below, I will give a simple example:
<!DOCTYPE html> <html> <head> <title>使用jQuery调用Ajax</title> <meta charset="utf-8"> <script src="https://cdn.bootcdn.net/ajax/libs/jquery/3.6.0/jquery.min.js"></script> <script> $(document).ready(function() { $.ajax({ url: 'test.php', type: 'POST', data: { name: '张三', age: 18 }, success: function(response) { console.log(response); } }); }); </script> </head> <body> <h1>使用jQuery调用Ajax示例</h1> </body> </html>In the above code, we first introduce the jQuery library. Then, after the page is loaded, we instantiate a jQuery object through the $(document).ready() function and use the $.ajax() function for asynchronous data interaction. In this example, we set the URL of the Ajax request to "test.php", the request method to POST, and passed two parameters (name and age). When the Ajax request is successful, we output the data returned by the server to the console.
In general, the "Ajax is not a method" prompt is usually caused by the jQuery library not being introduced correctly or the jQuery object not being instantiated. This problem can be easily solved by just checking the introduction and instantiation of the jQuery library. At the same time, we can also enter "$" or "jQuery" in the console to verify whether the jQuery object has been correctly introduced and instantiated.