How to properly handle expected parameter errors encountered

Question

function calculate(){
    echo "Number of parameters:" . func_get_args();
    echo "The third parameter is:" . func_get_arg(3);
    print_r(func_get_arg());
    $result = 0;
    foreach(func_get_arg() as $arg) :
        $result = $arg;
    end foreach;
    echo $result;

calculate(10, 20, 30, 1502);

How to solve this problem, I have a bad argument error in the variadic argument list of this function?

Answer 1

Latest versions of PHP do not allow a mismatch between the function parameter list and the parameter list in the call. You can use ellipses in the argument list to allow unlimited arguments instead of calling func_get_args().

function calculate(...$args){
    echo "参数个数：" . count($args) ;
    echo "第3个参数是：" . $args[3];
    print_r($args);
    $result = 0;
    foreach($args as $arg) :
        $result += $arg;
    end foreach;
    echo $result;
}