Clicking any button will trigger the handleSubmit function in Formik
P粉041881924
P粉041881924 2023-09-10 23:47:25
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I want to implement a check form for validating validity in the food ordering project using formik, but I encountered the problem of creating two buttons. No matter which button is clicked, handleSubmit will be called. How can I solve this problem?

The function goBack just sets the status to false.

export default function Checkout(props) {
  function handleSubmit(event) {
    // event.preventDefault();
    console.log("Hello");
  }

  return (
      <Formik
        initialValues={{ userName: "Hi", street: "", postalCode: "", city: "" }}
        onSubmit={handleSubmit}
      >
        {(props) => (
          <Form className={styles["form"]}>
            <div className={styles["form-control"]}>
              <div className={styles["form-control__input"]}>
                <label htmlFor="userName">Your name</label>
                <Field type="text" name="userName" id="userName"></Field>
              </div>
              <div className={styles["form-control__input"]}>
                <label htmlFor="street">Street</label>
                <Field type="text" name="street" id="street"></Field>
              </div>
              <div className={styles["form-control__input"]}>
                <label htmlFor="postalCode">Postal code</label>
                <Field type="text" name="postalCode" id="postalCode"></Field>
              </div>
              <div className={styles["form-control__input"]}>
                <label htmlFor="city">City</label>
                <Field type="text" name="city" id="city"></Field>
              </div>
            </div>
            <div className={styles["form-actions"]}>
              <CloseButton type="button" onClick={props.goBack}>Back</CloseButton>
              <OrderButton type="submit">Confirm</OrderButton>
            </div>
          </Form>
        )}
      </Formik>
  );
}
export default function CloseButton(props) {
  return <button type={props.type} onClick={props.onClick} className={styles["close-button"]}>{props.children}</button>;
}
export default function OrderButton(props) {
  return <button type={props.type} onClick={props.onClick} className={styles['order-button']}>{props.children}</button>
}

I want the CloseButton to close the form and return to the order list, but it only calls the handleSubmit created by the Formik component, not the function in the props. I read the documentation but nothing is mentioned about creating a formik with two buttons and is relevant to my question.

P粉041881924
P粉041881924

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P粉662361740

Looks like in props.goBack you want to reference the component's props, but you are actually using Formik's internal props (because it is the most recent props declaration). Since goBack is not defined on Formik's props, you are passing undefined as the onClick handler to the button.

The most direct way to solve this problem is to rename one of the props variables. I recommend naming Formik's props formikProps or something similar.

In my opinion, a better approach is to destructure the props (in both cases, although only one is necessary), like this:

export default function Checkout({ goBack }) {
  // ...
  return (
    <Formik>
      {(props) => (
        // ...
        <CloseButton type="button" onClick={goBack}>Back</CloseButton>
        // ...
      )}
    </Formik>
  )
}
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