I'm trying to find a way to search a JSON object and get a specific key, but search for another key.
This is a sample schema:
CREATE TABLE `fields` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `label` varchar(64) COLLATE utf8mb4_unicode_ci NOT NULL, `options` json DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci; INSERT INTO `fields` (label, options) VALUES ( 'My Field', '[{"text": "Grass", "value": "1"}, {"text": "Synthetic (New Type - Soft)", "value": "2"}, {"text": "Synthetic (Old Type - Hard)", "value": "3"}, {"text": "Gravel", "value": "5"}, {"text": "Clay", "value": "6"}, {"text": "Sand", "value": "7"}, {"text": "Grass/Synthetic Mix", "value": "8"}]' );
Database Fiddle: https://www.db-fiddle.com/f/npPgVqh7fJL2JweGJ5LWXE/1
So what I want is to select the string "Grass" from options
by providing the ID 1
.
But there seems to be no way to do this. I can get grass by doing this:
select JSON_EXTRACT(`options`, '$[0].text') from `fields`; // "Grass"
But this requires knowing the index of the array
I can partially get the index of the array like this:
select JSON_SEARCH(`options`, 'one', '1') from `fields`; // "$[0].value"
And get the index itself by doing something really scary like this:
select REPLACE(REPLACE(JSON_SEARCH(`options`, 'one', '1'), '"$[', ''), '].value"', '') from `fields`; // 0
Even achieving what I want by doing really scary things like this:
select JSON_EXTRACT(`options`,CONCAT('$[',REPLACE(REPLACE(JSON_SEARCH(`options`, 'one', '1'), '"$[', ''), '].value"', ''), '].text')) from `fields`; // "Grass"
But there must be a better way, right?
Database Fiddle: https://www.db-fiddle.com/f/npPgVqh7fJL2JweGJ5LWXE/1
MySQL 8.0 provides JSON_TABLE() to help handle such cases.
But you have to execute this complex JSON_TABLE() expression every time you want to write a query like this.
It would be simpler not to use JSON and instead store the data in a table with normal columns (one row per text/value pair). You can then search for the desired value in any column.
99% of the uses of JSON in MySQL that I see on Stack Overflow can be easily solved by not using JSON.